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3 years ago

What is the solution to this system of equations?

Mathematics

1 answer:

dlinn [17]3 years ago

7 0

Answer:

A. (5,2)

Step-by-step explanation:

If you go to solve the equation you would first try to get y by itself in the first equation and you would do that by subtracting x on both sides. Then you would have y=7-x and then you would plug the second equation in for the x and get the equation y=7-y-3 because you distribute the negative sign of the x to both the y and 3. Then you combine like terms and get y=4-y and then add the y to both sides and get 2y=4 and then divide both sides by 2 and get y=2. Then you plug in y in the first equation and get x+2=7. Then you subtract 2 from both sides and get x=5.

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Step-by-step explanation:

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Answer:

Just took the test,

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Step-by-step explanation:

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Read 2 more answers

{(4z-7,z-4,z) |z is any real number} z=-5

weeeeeb [17]

The set when z = -5 is {-27, -9, -5}

<h3>How to determine the set elements?</h3>

The set is given as:

{(4z-7,z-4,z) |z is any real number}

When z=-5, we have:

4z - 7 = 4(-5) - 7 = -27

z - 4 = -5 - 4 = -9

z = -5

So, we have:

{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}

Hence, the set when z = -5 is {-27, -9, -5}