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4 years ago

How much heat is lost when solid Al with a mass of 4110 g cools from 660.0 oC to 25.0 oC?

Chemistry

1 answer:

Leya [2.2K]4 years ago

6 0

Answer:

2,354,084.7 J

Explanation:

-We apply the Specific Heat Capacity formula to solve for the heat loss:

$Q=mc\bigtriangleup T$

where

m is the mass of the substance

Q is the heat loss/gain

c is the substance's specific heat

T is the change in temperature

\Substitute given values in the equation to solve for Q:

$Q=mc\bigtriangleup T\\\\\bigtriangleup T=933.15\ K-298.15\ K=635 \ K\\\\\therefore Q=4110\ g \times 0.902\ J/g\textdegree C\times 635 \ K\\\\=2,354,084.7 \ J$

Hence, the amount of heat lost is 2,354,084.7 J

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Answer:

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3 years ago

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2 years ago

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3 years ago

Which statement is true about BF3, a nonpolar molecule? It has nonpolar bonds and a symmetrical structure. It has nonpolar bonds

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3 years ago

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Answer:

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Explanation:

Please find the complete question in the attached file.

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