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Marina CMI [18]
3 years ago
11

How does salt alter the boiling point and freezing point of water

Chemistry
1 answer:
masha68 [24]3 years ago
8 0

Answer:

adding salt is like adding an impurity therefore the boiling point might increase from 100°c to maybe 102°c

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Please help me and dont send me a bitly link its a scam
melamori03 [73]

Answer:

Explanation:

4)6.27x10^20/(6.02x10^23)(u should have this number on your formula sheet)=0.001 mol

5)7.4x6.02x10^23=44.548x10^23atoms

6)molar mass for K is 39.10g/mol

3.27x39.10=127.86g

Im bad at sig figs. Just do it urself(:p

6 0
3 years ago
What is the volume of 7.50 x 10^24 molecules of NH3 at STP?
Allushta [10]

27.9L

Explanation:

Given parameters:

Number of molecules = 7.5 x 10²⁴molecules

Condition = STP

Unknown:

Volume of gas = ?

Solution;

The volume of gas at STP is expressed below;

 Volume of gas = number of moles x 22.4

Number of moles = \frac{Number of molecules }{6.02 x 10^{23} }

    Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;

     Number of moles of NH₃ =  \frac{[tex]7.5 x 10^{24} }{6.02 x 10^{23} }[/tex]

   Number of moles of NH₃ = 12.5moles

Volume of gas = 12.5 x 22.4 = 27.9L

learn more:

Volume of gas at STP brainly.com/question/7795301

#learnwithBrainly

3 0
3 years ago
How many valence electrons are in the electron-dot structures for the elements in group 3a(13)?
frosja888 [35]
Three valence electrons
3 0
3 years ago
What is the percent by mass of nahco3 in a solution containing 10 g of nahco3 dissolved in 400 ml of h2o?
Marat540 [252]
Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
7 0
3 years ago
What does it mean for a gene to be active?
nikklg [1K]

Answer: You should be able to find the answer on the internet

4 0
3 years ago
Read 2 more answers
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