Answer:
Explanation:
4)6.27x10^20/(6.02x10^23)(u should have this number on your formula sheet)=0.001 mol
5)7.4x6.02x10^23=44.548x10^23atoms
6)molar mass for K is 39.10g/mol
3.27x39.10=127.86g
Im bad at sig figs. Just do it urself(:p
27.9L
Explanation:
Given parameters:
Number of molecules = 7.5 x 10²⁴molecules
Condition = STP
Unknown:
Volume of gas = ?
Solution;
The volume of gas at STP is expressed below;
Volume of gas = number of moles x 22.4
Number of moles = 
Now if we can obtain the value of the number of moles from the expression above, we can plug it back into the equation of the volume of gas at STP;
Number of moles of NH₃ =
}{6.02 x 10^{23} }[/tex]
Number of moles of NH₃ = 12.5moles
Volume of gas = 12.5 x 22.4 = 27.9L
learn more:
Volume of gas at STP brainly.com/question/7795301
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Answer is: the percent by mass of NaHCO₃ is 2,43%.
m(NaHCO₃) = 10 g.
V(H₂O) = 400 ml.
d(H₂O) = 1 g/ml.
m(H₂O) = V(H₂O) · d(H₂O).
m(H₂O) = 400 ml · 1 g/ml.
m(H₂O) = 400 g.
m(solution) = m(H₂O) + m(NaHCO₃).
m(solution) = 400 g + 10 g.
m(solution) = 410 g.
ω(NaHCO₃) = 10 g ÷ 410 g · 100%.
ω(NaHCO₃) = 2,43 %
Answer: You should be able to find the answer on the internet