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Effectus [21]
4 years ago
9

Tia has a sample of pure gold (Au). She weighed the sample and the result was 35.9 grams. Tia wants to determine the number of a

toms in the sample. Calculate the number of atoms in 35.9 g of pure gold.
Chemistry
2 answers:
Gemiola [76]4 years ago
4 0
First, find moles of gold given the mass of the sample:
(35.9g Au)/(197.0g/mol Au) = 0.182mol Au

Second, multiply moles of Au by Avogrado's number:
(0.182mol)(6.02 x10^23)= 1.10x10^23 atoms Au
IRINA_888 [86]4 years ago
3 0

Answer: 1.09\times 10^{23atoms of gold.

Explanation: To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}

For gold

Mass of gold given = 35.9 g

Molar mass of gold = 197 g/mol

Putting values in above equation, we get:

\text{Moles of gold}=\frac{35.9g}{197g/mol}=0.18mol

According to Avogadro's law, 1 mole of every substance contains avogadro's number (6.023\times 10^{23}) of particles.

Thus 0.18 moles of gold will contain=\frac{6.023\times 10^{23}}{1}\times 0.18=1.09\times 10^{23} atoms of gold.

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The most abundant elements in the body are _____.
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Mitosis and Meiosis Lab Report
poizon [28]

Answer:

Mitosis and Meiosis Lab Report

Instructions: In the Mitosis and Meiosis lab, you investigated sexual and asexual reproduction as well as the processes of cellular division by mitosis and meiosis. Record your observations in the lab report below. You will submit your completed report.

________________________________________

Name and Title:  

Mitosis and Meiosis Lab Report.  

Objective(s):  

To learn and explore what mitosis and meiosis is and what they do.  

Hypothesis:

Record your predictions during the zoo tour section of the lab in the data chart.

Procedure:

First, go into the mitosis and meiosis cycles. Then look at what happens when a sex cell from a female tiger is combined with a sex cell from a male tiger. Then investigate what happens when two starfish reproduce asexually. Then write down the predictions about how each organism will replicate. Then, keep track on whether or not the forecast was right.

Data:  

Record your data from the zoo tour in the data chart below. Be sure to fill in the chart completely.

Zoo Organism Reproduction Prediction

(sexual, asexual, or both) Reproduction Result

(sexual, asexual, or both)

Elephant Sexual Sexual

Whiptail lizard Asexual Asexual

Parrot Sexual Sexual

Redwood tree  Both Both

Amoeba Asexual Asexual

Jellyfish Asexual Both

Conclusion:  

Your conclusion will include a summary of your lab results and an interpretation of the results. Please write in complete sentences.

1. List one-way mitosis and meiosis are the same and one way they are different.

Meiosis has 2 cell divisions, but mitosis has just one cell division. Since the parent cell develops diploid cells, meiosis I is the same as mitosis. The distinction between meiosis and mitosis is that after the whole process, meiosis produces genetically distinct haploid daughter cells, while mitosis produces genetically identical diploid daughter cells.

2. What is one advantage and one disadvantage of sexual reproduction?

The greatest benefit of sexual reproduction is that it aids in the development of offspring that are well suited to environmental environments due to genetic differentiation. As a result, the nation has a diverse range of descendants. The downside is that it needs two parents and takes longer than asexual reproduction.

3. What is one advantage and one disadvantage of asexual reproduction?

Asexual reproduction has the advantage of requiring only one parent, taking a short amount of time, and producing genetically identical offspring. The only drawback is that when there is a catastrophe, the mortality rate is poor due to the generation of genetically identical offspring.

4. Some living organisms are capable of both asexual and sexual reproduction. Explain how this can be an advantage.

To produce offspring, the organism may use either sexual or asexual reproduction. If it is difficult to find a mate, the living being will use asexual reproduction to produce offspring quickly. Sexual reproduction is possible because the individual requires genetically distinct offspring for survival.

Explanation:

Try to paraphrase evrything. I already paraphrased the procedure but i reccomend using the website "quillbot" to paraphrase evrything else so you dont get in trouble! If you have any qustions im here to answer ;)

6 0
3 years ago
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A volume of 500.0 mL of 0.160 M NaOH is added to 585 mL of 0.200 M weak acid ( K a = 1.28 × 10 − 5 ) . What is the pH of the res
Hitman42 [59]

Answer : The pH of the resulting buffer is, 5.22

Explanation : Given,

K_a=1.28\times 10^{-5}

First we have to calculate the moles of NaOH\text{ and }HA

\text{Moles of }NaOH=\text{Concentration of }NaOH\times \text{Volume of solution}}=0.160M\times 0.500L=0.08mol

and,

\text{Moles of }HA=\text{Concentration of }HA\times \text{Volume of solution}}=0.200M\times 0.585L=0.117mol

The balanced chemical reaction is:

HA+(aq)+OH^-(aq)\rightarrow H_2O(l)+A^-(aq)

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Moles of A^- = 0.08 mol

The expression used for the calculation of pK_a is,

pK_a=-\log (K_a)

Now put the value of K_a in this expression, we get:

pK_a=-\log (1.28\times 10^{-5})

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Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

pH=pK_a+\log \frac{[Salt]}{[Acid]}

pH=pK_a+\log \frac{[A^-]}{[HA]}

Now put all the given values in this expression, we get:

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3 years ago
What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 gram and the mass of collec
mariarad [96]

Answer: The percentage composition of hydrogen in the given compound is 15%.

Explanation:

To calculate the percentage composition of hydrogen in a compound, we use the formula:

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Where,

Mass of hydrogen = 41.4 grams

Mass of compound = 276 grams

Putting values in above equation, we get:

\%\text{ composition of hydrogen}=\frac{41.4g}{276}{\times 100

Percentage composition of hydrogen in a given compound = 15%

8 0
3 years ago
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