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max2010maxim [7]

3 years ago

10

How do I find the area of a square

2 answers:

Semenov [28]3 years ago

7 0

Answer:

Step-by-step explanation:

The area of a square can be found by multiplying the base times itself. This is similar to the area of a rectangle but the base is the same length as the height. If a square has a base of length 6 inches its area is 6*6=36 square inches

Likurg_2 [28]3 years ago

6 0

The area of a square would be = A= a²

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No entiendo ayudaaaa

hram777 [196]

This is a pythagorean theorem problem therefore a^2+b^2=c^2
a=8, b=?, c=10
8^2+b^2=10^2
64+b^2=100
100-64=56
square root of b^2=square root of 56
b=2 rad14
2 rad14 +4=
2 (rad14 + 1)= ANSWER

4 0

3 years ago

The compound amount is $…The amount of interest earned is $…

nadya68 [22]

In order to calculate the compound amount and the amount of interest earned, we can use the formula below:

$A=P\cdot(1+\frac{i}{n})^{nt}$

Where A is the compound amount after t years, P is the principal (initial amount) i is the interest rate and n is how many times the interest is compounded in a year.

So, for P = 71000, i = 0.0102, t = 4 and n = 4, we have:

$\begin{gathered} A=71000\cdot(1+\frac{0.0102}{4})^{4\cdot4}_{} \\ A=71000\cdot(1+0.00255)^{16} \\ A=73952.87 \end{gathered}$

Therefore the compound amount is $73952.87

The amount of interest is:

$\begin{gathered} I=A-P \\ I=73952.87-71000 \\ I=2952.87 \end{gathered}$

So the amount of interest earned is $2952.87.

3 0

2 years ago

Drag each tile to the correct box.

Anni [7]

Answer:

$3x^{2}y^{2}\sqrt[4]{7xy^{3}}$ .

Step-by-step explanation:

Since we have to find the simplified form of the expression as below

$\sqrt[4]{567x^{9}y^{11}}$

we will solve the expression as below

$=[567x^{9}y^{11}]^{\frac{1}{4}}$

$=(81\times 7)^{\frac{1}{4}}\times x^{\frac{9}{4}}\times y^{\frac{11}{4}}$

$=81^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{\frac{8}{4}+\frac{1}{4}}.y^{\frac{8}{4}+\frac{3}{4}}$

$=(3^{4})^{\frac{1}{4}}.7^{\frac{1}{4}}.x^{2+\frac{1}{4}}.y^{2+\frac{3}{4}}$

$=3^{1}.7^{\frac{1}{4}}.x^{2}.x^{\frac{1}{4}}.y^{2}.y^{\frac{3}{4}}$

$=3.x^{2}.y^{2}.(7^{\frac{1}{4}}.x^{\frac{1}{4}}.y^{\frac{3}{4}})$

$=3x^{2}y^{2}.(7xy^{3})^{\frac{1}{4}}$

$=3x^{2}y^{2}\sqrt[4]{7xy^{3}}$ .

7 0

3 years ago

A medical researcher says that less than 87â€‹% of adults in a certain country think that healthy children should be required to

Lyrx [107]

Answer: It is not enough evidence to support the researcher's claim.

Step-by-step explanation:

Since we have given that

n = 500

$\hat{p}=0.85$

So, the hypothesis are as follows:

$H_0:\hat{p}$

So, the z value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.85-0.87}{\sqrt{\dfrac{0.87\times 0.13}{500}}}\\\\z=\dfrac{-0.02}{0.015}\\\\z=-1.33$

At α = 0.05

z= -1.64

So, 1.64<-1.33

So, we accept the null hypothesis.

Hence, it is not enough evidence to support the researcher's claim.

3 0

3 years ago

The product of 32 and an unknown number subtracted from 435 is 179.

S_A_V [24]

435-32n=179 would be the equation im pretty sure.

6 0

3 years ago

Read 2 more answers