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zzz [600]
2 years ago
7

Suppose point j is the midpoint of segment lm where j(5, -1) and m(0, 6). what are the coordinates of end point l?

Mathematics
1 answer:
zalisa [80]2 years ago
3 0

If the midpoint of segment lm where j(5, -1) and m(0, 6), then the coordinates of end point l is (10,-8)..

Midpoint:

Midpoint of a line segment is the point that is halfway between the endpoints of the line segment.

The formula for the midpoint is,

(x_m,y_m)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

where,

(x_m,y_m) = coordinates of the midpoint

(x₁, y₁)   = coordinates of the first point

(x₂, y₂) = coordinates of the second point

Given,

Midpoint = j = (5,-1)

Second point =  m = (0,6)

Now, we have to find the first midpoint l.

Let (x,y) be the coordinates of l.

Then apply the values on the formula,

Then we get,

(5,-1)=(\frac{x+0}{2},\frac{y+6}{2})

Compare the values in order to find the coordinates,

=> 5 = (x + 0) / 2

=> 5 x 2 = x + 0

=> 10 = x

Similarly,

=> -1 = (y + 6) / 2

=> -1 x 2 = y + 6

=> -2 = y + 6

=> -2 - 6 = y

=> y = -8

Therefore, the coordinates of l is (10,-8).

To know more about Midpoint here.

brainly.com/question/28224145

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A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that t
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Answer:

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

Step-by-step explanation:

A publisher reports that 75% of their readers own a particular make of car. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage.

At the null hypothesis, we test if the proportion is of 75%, that is:

H_0: p = 0.75

At the alternate hypothesis, we test if the proportion is different of 75%, that is:

H_1: p \neq 0.75

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

75% is tested at the null hypothesis:

This means that \mu = 0.75, \sigma = \sqrt{0.75*0.25}

A random sample of 280 found that 70% of the readers owned a particular make of car.

This means that n = 280, X = 0.7

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.7 - 0.75}{\frac{\sqrt{0.75*0.25}}{\sqrt{280}}}

z = -1.93

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion differing from 0.75 by at least |0.7 - 0.75| = 0.05, which is P(|z| > 1.93), which is 2 multiplied by the p-value of z = -1.93.

Looking at the z-table, z = -1.93 has a p-value of 0.0268.

2*0.0268 = 0.0536.

The p-value of the test is of 0.0536 > 0.02, which means that there is not sufficient evidence at the 0.02 level to support the executive's claim.

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