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zzz [600]
1 year ago
7

Suppose point j is the midpoint of segment lm where j(5, -1) and m(0, 6). what are the coordinates of end point l?

Mathematics
1 answer:
zalisa [80]1 year ago
3 0

If the midpoint of segment lm where j(5, -1) and m(0, 6), then the coordinates of end point l is (10,-8)..

Midpoint:

Midpoint of a line segment is the point that is halfway between the endpoints of the line segment.

The formula for the midpoint is,

(x_m,y_m)=(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})

where,

(x_m,y_m) = coordinates of the midpoint

(x₁, y₁)   = coordinates of the first point

(x₂, y₂) = coordinates of the second point

Given,

Midpoint = j = (5,-1)

Second point =  m = (0,6)

Now, we have to find the first midpoint l.

Let (x,y) be the coordinates of l.

Then apply the values on the formula,

Then we get,

(5,-1)=(\frac{x+0}{2},\frac{y+6}{2})

Compare the values in order to find the coordinates,

=> 5 = (x + 0) / 2

=> 5 x 2 = x + 0

=> 10 = x

Similarly,

=> -1 = (y + 6) / 2

=> -1 x 2 = y + 6

=> -2 = y + 6

=> -2 - 6 = y

=> y = -8

Therefore, the coordinates of l is (10,-8).

To know more about Midpoint here.

brainly.com/question/28224145

#SPJ4

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Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negat
avanturin [10]

Answer:

Answer:

(5, 20)  

Step-by-step explanation:

We can find the slope of the line

m = (y2-y1)/(x2-x1)

   = (40-0)/(10-0)

   = 40/10

   =4

Since the line goes through (0,0) the y intercept is 0

y = mx+b

y = 4x

Lets check the points  by substituting into the equation

40, 10)     10 = 4*40   10 =160  no

(–5, –10)    -10 = 4*-5    10 = -20   no

(5, 20)       20 = 4*5    20 = 20  yes

(–10, –20)    -20 = 4*-10    -20 = -40   no

Step-by-step explanation:

Which ordered pair would form a proportional relationship with the point graphed below? On a coordinate plane, a line with negative slope goes through points (negative 20, 10), (0, 0), and (20, negative 10). (10, –20) (–30, 20) (–10, 5) (35, –20)

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3 years ago
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The diagram shows 3 ships A, B and C at sea.
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Answer:

5km + 4.5km +2.7km = 12.3km

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2 years ago
Solve the inequality
GenaCL600 [577]
-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
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6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2

-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6

so y > = 9/6(or 1 1/2) or y < = -6


3 0
3 years ago
How many solutions does the following system of equations have y=2x+2 &amp; 2y=4x+4
iren [92.7K]

Answer:

y=2x + 2

0= 2x +2

-2x = 2

x= -1

Step-by-step explanation:

2y = 4x +4

2y -4x =4

y-2x =2

-2x +y =2

2x-y=-2

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2 years ago
Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri
Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after \frac{640}{7} miles

Step-by-step explanation:

Given

The table represents the car mileage

y = -\frac{1}{5}x + 31 --- The van

First, calculate the car's slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)

So, we have:

m = \frac{10.5 - 13.5}{180 - 60}

m = \frac{-3}{120}

m = -\frac{1}{40}

Calculate the equation using:

y = -\frac{1}{40}(x - 60)+13.5

y = -\frac{1}{40}x + 1.5+13.5

y = -\frac{1}{40}x + 15

m = -\frac{1}{40} implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

y = -\frac{1}{5}x + 31 --- The van

By comparison to: y = mx + b

m = -\frac{1}{5}

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

1/40 < 1/5

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

y = -\frac{1}{5}x + 31 --- The van

y = -\frac{1}{40}x + 15 --- The car

Equate both

-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15

Collect like terms

\frac{1}{40}x -\frac{1}{5}x  =-31 + 15

\frac{1}{40}x -\frac{1}{5}x  =-16

Take LCM

\frac{x - 8x}{40} = -16

\frac{- 7x}{40} = -16

Solve for -7x

-7x = -640

Solve for x

x = \frac{640}{7}

5 0
3 years ago
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