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torisob [31]
3 years ago
9

1) Calculate the potential energy of a 5.00 kg object sitting on a 3.00 meter high ledge.

Physics
1 answer:
maria [59]3 years ago
5 0

Answer:

15kg

Explanation:

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A long string is wrapped around a 6.6-cm-diameter cylinder, initially at rest, that is free to rotate on an axle. The string is
lys-0071 [83]

Answer:

\omega_f=571.42\ rpm

Explanation:

It is given that,

Diameter of cylinder, d = 6.6 cm

Radius of cylinder, r = 3.3 cm = 0.033 m

Acceleration of the string, a=1.5\ m/s^2

Displacement, d = 1.3 m

The angular acceleration is given by :

\alpha =\dfrac{a}{r}

\alpha =\dfrac{1.5}{0.033}

\alpha =45.46\ rad/s^2

The angular displacement is given by :

\theta=\dfrac{d}{r}

\theta=\dfrac{1.3}{0.033}

\theta=39.39\ rad

Using the third equation of rotational kinematics as :

\omega_f^2-\omega_i^2=2\alpha \theta

Here, \omega_i=0

\omega_f=\sqrt{2\alpha \theta}

\omega_f=\sqrt{2\times 45.46\times 39.39}

\omega_f=59.84\ rad/s

Since, 1 rad/s = 9.54 rpm

So,

\omega_f=571.42\ rpm

So, the angular speed of the cylinder is 571.42 rpm. Hence, this is the required solution.

5 0
3 years ago
An electric field of 1.27 kV/m and a magnetic field of 0.490 T act on a moving electron to produce no net force. If the fields a
lesantik [10]

Answer:

v = 2591.83 m/s

Explanation:

Given that,

The electric field is 1.27 kV/m and the magnetic field is 0.49 T. We need to find the electron's speed if the fields are perpendicular to each other. The magnetic force is balanced by the electric force such that,

qE=qvB\\\\v=\dfrac{E}{B}\\\\v=\dfrac{1.27\times 10^3}{0.49}\\\\v=2591.83\ m/s

So, the speed of the electron is 2591.83 m/s.

8 0
3 years ago
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 3.9 m/s. The car is a distanc
sammy [17]
If it takes t seconds to reach the car, then the distance d is 3.9t.

The bear's distance from the tourist's starting point is
6t-23

For maximum d, we set the equations equal to each other:
3.9t=6t-23
\Rightarrow -2.1t=-23
\Rightarrow t=\frac{23}{2.1}
so the distance is
d=3.9(\frac{23}{2.1})\approx42.741\ m
6 0
3 years ago
4. Why is it better to use data from three or more seismic stations to find the epicenter of an earthquake?
svetoff [14.1K]
Ilana is togladly hospitalized for the loss and the loss and her family of the dead were in a coma and she had to go on the plane and then to go to a hotel and to see if the girl had a child and a woman was in a car crash or something like it could have caused a lot to happen with her body that could help him get out the next morning after a long day of work and a woman was in a condition of a new yo girl in her apartment and was taken into a car in a coma at a
6 0
3 years ago
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A long, straight, vertical wire carries a current upward. due east of this wire, in what direction does the magnetic field point
Solnce55 [7]
(I assume that the 4 directions north-south-east-west are meant with respect to the wire seen from the top.)

We can use the right-hand rule to understand the direction of the magnetic field generated by the wire. The thumb follows the direction of the current in the wire (upward), while  the other fingers give the direction of the field in every point around the wire. Seen from the top, the field has an anti-clockwise direction. Therefore, if we take a point at east with respect to the wire, in this point the field has direction south.
8 0
3 years ago
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