Answer:
Current amplitude, I = 5.57 A
Explanation:
It is given that,
Effective resistance, R = 22 ohms
Inductive reactance, L = 72 ohms
Voltage of the alternating source, V = 420 volt
The total impedance of the RL circuit is given by :
Z = 75.28 ohms
From Ohm's law,
I = 5.57 A
So, the current amplitude of the electric motor is 5.57 A. Hence, this is the required solution.
If the forces are equal, at a distance equidistant it is not possible to act a pair on the body since both torques cancel each other. Being of the same magnitude and in the opposite direction, the sum of the torques will be zero.
Answer:
The correct option is;
B. Subtract vectors A from C; = 12 N
Explanation:
The given parameters are;
The weight of the dresser = 250 N
The force applied by the man = 20 N = C
The frictional force provided by the carpet = 8 N = The component of the weight resisting motion = A
Therefore, the net force tending to put the dresser in motion, , is given as follows;
= The force applied by the man, C - The frictional force provided by the carpet which is the component of the weight resisting motion, A
= C - A = 20 N - 8 N = 12 N
= 12 N
The resulting net force, = 12 N.