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aleksley [76]
3 years ago
11

A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of

the torque on the dipole when (a) the dipole is parallel to the electric field,
Physics
1 answer:
Over [174]3 years ago
8 0

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

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POTENTIAL I KINETIC ENERGY
TEA [102]

7kinetic energy is decreasing in B

4 0
2 years ago
Explain how atomic interactions determine a material to be transparent and opaque?
motikmotik

Answer:

Explanation below.

Explanation:

It should be understood that transparency is caused through or by the transmission of light waves. This means that, If or when the energy known as the vibrational energy of a light wave is passed through the object, then the object appears clear, or transparent. And when or If the energy only causes vibrations in the surface before reflecting off the object, then the object will appear opaque, that is nontransparent.

7 0
3 years ago
A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf
lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf=E_{rms}=120 V

We have to find the length of the wire from which the coil is made.

Peak value of emf=E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V

Length of wire=4\sqrt{\frac{NE_0}{2\pi fB}}

Substitute the values

Length of wire=4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

6 0
3 years ago
A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 20
Klio2033 [76]

Answer:

\boxed{{\boxed{\blue{ 12.5}}}}

Explanation:

Given, for girl : Weight or force;

\rm \: F_1 = 50 \: kgf

Area of both heels;

\rm \: A_1 =  \; 2 ×1 \;  cm^2 = 2  \: cm^2

\rm \: Pressure \:  P_1  =  \cfrac{F_1}{ A_1 }  =  \dfrac{50 \: kgf}{2 \: cm {}^{2} }  = 25 \: kgf \: cm {}^{ - 1}

For elephant, Weight = Force \rm F_2 = 2000 kg•f

Area of 4 feet;

\rm \: A_2  = \; 4 \times 250 \;  cm^2 = 1000 \:  cm^2

\rm \: Pressure \:  P_2 = {F_2}/{A_2} \;  = \cfrac{2 \cancel{0 00 }\:  kgf}{1 \cancel{000} \: cm^2} =  2 \: kgf \: { \:cm}^{- 1}

Now;

\rm  = \dfrac{Pressure \:  Exerted  \: by  \: the \:  Girl}{Pressure  \: exerted  \: by \:  the  \: elephant}

=  \rm \: P_1/P_2

\implies    \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } =  \rm\cfrac{25 \:  \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5}

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

I aspire this helps!

3 0
2 years ago
Stick a fork into each end of the root vegetable as shown. The forks should be on the same side of the vegetable, and
zhuklara [117]

Answer:

Yes

Explanation:

There is a position that works better than this and that is switching the sides of the forks.

7 0
3 years ago
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