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Burka [1]
2 years ago
13

You are standing in an elevator that is accelerating upward. The magnitude

Physics
1 answer:
brilliants [131]2 years ago
3 0

Answer:

All for da gang

The net force on you changes from zero to downward as the elevator begins accelerating.

Explanation:

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2 years ago
A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed
stich3 [128]

Answer:

Distance of closest approach, r=1.91\times 10^{-14}\ m

Explanation:

It is given that,

Charge on proton, q_p=e

Charge on alpha particle, q_a=2e

Mass of proton, m_p=1.67\times 10^{-27}\ kg

Mass of alpha particle, m_a=4m_p=6.68\times 10^{-27}\ kg

The distance of closest approach for two charged particle is given by :

r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}

r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}

r=1.91\times 10^{-14}\ m

So, their distance of closest approach, as measured between their centers 1.91\times 10^{-14}\ m. Hence, this is the required solution.

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3 years ago
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