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Burka [1]
2 years ago
13

You are standing in an elevator that is accelerating upward. The magnitude

Physics
1 answer:
brilliants [131]2 years ago
3 0

Answer:

All for da gang

The net force on you changes from zero to downward as the elevator begins accelerating.

Explanation:

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If two cars are 5 m apart, and one car has a mass of 2,565 kg and the other
alekssr [168]

Answer:

D

Explanation:

just did

7 0
3 years ago
Two spherical shells have a common center. A -2.1 10-6 C charge is spread uniformly over the inner shell, which has a radius of
julsineya [31]

Answer:

a) E_total = 6,525 10⁴ N /C ,field direction is radial outgoing

b)  E_total = 1.89 10⁶ N / C, field is incoming radial

c) E_total = 0

Explanetion:

For this exercise we can use that the charge in a spherical shell can be considered concentrated at its center and that the electric field inside the shell is zero, since Gauss's law is

                Ф = E .dA = q_{int} /ε₀

inside the spherical shell there are no charges

The electric field is a vector quantity, so we calculate the field created by each shell and add it vectorly.

We have two sphere shells with radii 0.050m and 0.15m respectively

a) point where you want to know the electric field d = 0.20 m

shell 1

the point is on the outside,d>ro,  therefore we can consider the charge to be concentrated in the center

            E₁ = k q₁ / d²

             

shell 2

the point is on the outside,d>ro

             E₂ = k q₂ / d²

the total camp is

              E_total = -E₁ + E₂

              E_total = k ( \frac{-q_1 + q_2}{d^2})

              E_total = 9 10⁹ (-2.1 10⁻⁶+ 5 10⁻⁶ / .2²

              E_total = 6,525 10⁵ N /C

The field direction is radial and outgoing ti the shells

b) the calculation point is d = 0.10m

shell 1

point outside the shell d> ro

                 E₁ = k q₁ / d²

shell 2

the point is inside the shell d <ro

Therefore, according to Gauss's law, since there are no charges in the interior, the electrioc field is zero

                E₂ = 0

               

                 E_total = E₁

                 E_total = k q₁ / d²

                 E_total = 9 10⁹ 2.1 10⁻⁶ / 0.1²

                 E_total = 1.89 10⁶ N / A

As the charge is negative, this field is incoming radial, that is, it is directed towards the shell 1

c) the point of interest d = 0.025 m

shell 1

point  is inside the shell d< ro

                 

as there are no charges inside

                     E₁ = 0

shell 2

point is inside the radius of the shell d <ro

                    E₂ = 0

the total field is

                    E_total = 0

3 0
3 years ago
Which of the following statements is true?
Bad White [126]
The answer is c hope this helps



6 0
3 years ago
Read 2 more answers
What are atoms and elements?
gizmo_the_mogwai [7]

Answer:

Atom, smallest unit into which matter can be divided without the release of electrically charged particles.

an element is a pure substance which cannot be broken down by chemical means

3 0
3 years ago
Read 2 more answers
A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-
Alisiya [41]
First we need to convert the angular speed from rpm to rad/s. Keeping in mind that 
1 rev= 2 \pi rad
1 min = 60 s
the angular speed is
\omega = 7.18  \frac{rev}{min} \cdot  \frac{2 \pi}{60} = 0.75 rad/s

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s
3 0
3 years ago
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