2 years ago

You are standing in an elevator that is accelerating upward. The magnitude

Physics

1 answer:

brilliants [131]2 years ago

3 0

Answer:

All for da gang

The net force on you changes from zero to downward as the elevator begins accelerating.

Explanation:

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Distance of closest approach, $r=1.91\times 10^{-14}\ m$

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It is given that,

Charge on proton, $q_p=e$

Charge on alpha particle, $q_a=2e$

Mass of proton, $m_p=1.67\times 10^{-27}\ kg$

Mass of alpha particle, $m_a=4m_p=6.68\times 10^{-27}\ kg$

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$r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}$

$r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}$

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So, their distance of closest approach, as measured between their centers $1.91\times 10^{-14}\ m$ . Hence, this is the required solution.

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