Answer:
1) 64.2 mi/h
2) 3.31 seconds
3) 47.5 m
4) 5.26 seconds
Explanation:
t = Time taken = 2.5 s
u = Initial velocity = 0 m/s
v = Final velocity = 21.7 m/s
s = Displacement
a = Acceleration
1) Top speed = 28.7 m/s
1 mile = 1609.344 m

1 hour = 60×60 seconds


Top speed of the cheetah is 64.2 mi/h
Equation of motion

Acceleration of the cheetah is 8.68 m/s²
2)

It takes a cheetah 3.31 seconds to reach its top speed.
3)

It travels 47.5 m in that time
4) When s = 120 m

The time it takes the cheetah to reach a rabbit is 120 m is 5.26 seconds
A) average acceleration = final velocity - initial velocity / time
= 7700 - 0 / 11
= 700ms^-2
B) force = mass x acceleration
= (3.05 x 105) x 700
= 320.25 x 700
= 224,175N
Answer:
- The distance between the charges is 5,335.026 m
Explanation:
To obtain the forces between the particles, we can use Coulomb's Law in scalar form, this is, the force between the particles will be:

where k is Coulomb's constant,
and
are the charges and d is the distance between the charges.
Working a little the equation, we can take:


And this equation will give us the distance between the charges. Taking the values of the problem

(the force has a minus sign, as its attractive)




And this is the distance between the charges.
Wavelength = (speed) / (frequency)
= (3 x 10⁸ m/s) / (1 x 10⁸ /s) = 3 meters
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