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3 years ago

Find the area of a triangle whose base is 5cm and whose height is 12cm.

2 answers:

6 0

By definition, the area of the triangle is given by:
$A = (1/2) * (b) * (h)
$
Where,
b: base
h: height
Substituting values we have:
$A = (1/2) * (5) * (12)

 A = 30 cm ^ 2$
Answer:
The area of a triangle whose base is 5cm and whose height is 12cm is:
A = 30 cm ^ 2

Elina [12.6K]3 years ago

3 0

A=30. The formula to find the area of a triangle is. 1/2(base x height)

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1. What is a perfect square? 2. What is the square root of 4x²? 3. What is the square root of 25? 4. Factor 4x² + 20x + 25.

Ulleksa [173]

Answer:

Step-by-step explanation:

1) A perfect square is a whole number which is a product of a smaller whole number and itself. Examples of perfect squares are

4(2 × 2)

9(3 × 3)

16(4 × 4)

25(5 × 5)

36(6 × 6)

2) Square root of 4x² is 2x(product of square root of 4 and square root of x²)

3) square of 25 is 5

4) 4x² + 20x + 25

The general formula for solving quadratic equations is expressed as

x = [- b ± √(b² - 4ac)]/2a

From the equation given,

a = 4

b = 20

c = 25

Therefore,

x = [- 20 ± √(20² - 4 × 4 × 25)]/2 × 4

x = [- 20 ± √(400 - 400)]/8

x = [- 20 ± 0]/8

x = - 20/8

x = - 2.5

3 0

3 years ago

Maksim231197 [3]

Answer:

D. x=1

Step-by-step explanation:

Image can be rewritten as 3x + 6 = 9.

Solve for x.

3x +6 = 9

Isolate x by subtracting 6 from both sides.

3x = 3

Get rid of the 3 by dividing by 3 on both sides.

x = 1

Hope this helped.

8 0

3 years ago

A cylinder has a height of 18 millimeters and a radius of 18 millimeters. What is its volume? Use ≈ 3.14 and round your answer

solong [7]

Answer:

$Volume = 18312.48$

Step-by-step explanation:

Given

$Height (h) = 18mm$

$Radius (r) = 18mm$

Required

Determine the volume

The volume of a cylinder is calculated as thus:

$Volume = \pi r^2h$

Substitute values for r and h

$Volume = 3.14 * 18^2 * 18$

$Volume = 18312.48$

<em>Hence, the volume of the cylinder is 18312.48mm³</em>

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3 years ago

True or false - A reflection is an example of a rigid transformation?

Ray Of Light [21]

True
Lengths are preserved during a reflection, meaning it is rigid.

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3 years ago

Media experts claim that daily print newspapers are declining because of Internet access. Listed below, from left to right and

yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(d) The p value is 1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean, $\bar{x}_{1}$ = 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean, $\bar{x}_{2}}$ = 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

$t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}$

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic $t_{\alpha/2}$ = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

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3 years ago