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alex41 [277]
3 years ago
15

The plant-breeding department at a major university developed a new hybrid boysenberry plant called Stumptown Berry. Based on re

search data, the claim is made that from the time shoots are planted 90 days on average are required to obtain the first berry. A corporation that is interested in marketing the product tests 60 shoots by planting them and recording the number of days before each plant produces its first berry. The sample mean is 92.3 days. The corporation wants to know if the mean number of days is different from the 90 days claimed. What are the correct hypotheses?
Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

\text{Null hypothesis}: H_0:\mu=90\\\\\text{Alternative Hypothesis}:\mu\neq 90

Step-by-step explanation:

Given claim : From the time shoots are planted 90 days on average are required to obtain the first berry.

. The sample mean is 92.3 days. The corporation wants to know if the mean number of days is different from the 90 days claimed.

As we know that the null hypotheses shows there is no statistical difference between the groups but the alternative hypothesis is opposite to it, it shows there is difference.

Thus , the correct hypotheses will be :-

\text{Null hypothesis}: H_0:\mu=90\\\\\text{Alternative Hypothesis}:\mu\neq 90

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Answer:

Step-by-step explanation:

10000*4%= 400 Geese year1

10400*4%=416 Geese  year 2

10816*4%= 432.64 Geese year 3

11,248.64*4%= 449.95 Geese. year 4

11248.64+449.95= 11698.59

11698.59-10000=1698.59

Increased by 1699 Geese.

3 0
3 years ago
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Let f(x) = ............
34kurt

Answer:

So first lets find g(-1)

so we plug in the answers:

-2 * -1 ^2 -4

-2*1-4 = -2-4 =

-6

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4-3=1

-6+1 = 5

3*5 = 15

Im getting answer of 15 but it shows -15 or something, so I dont know if I got it wrong or if its like a dash then the answer.

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3 years ago
: Roland currently makes $6 million in the league, and could use more player development. His hometown team, the Dawgs, are inte
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No

Step-by-step explanation:

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3 years ago
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Stock A ‘s returns have a standard deviation of 0.5, and stock B’s returns have standard deviation of 0.6.The correlation coeffi
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Answer:

The variance of the profile is 0.2179.

Step-by-step explanation:

We are given the following in the question:

\sigma_A = 0.5\\\sigma_B = 0.6\\\rho_{A,B} = 0.5\\w_A = 70\% = 0.7\\w_B = 30\% = 0.3

Variance of portfolio is given by:

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}

Cov_{A,B} = \rho_{A,B} \times \sigma_A \times \sigma_B \\=0.5\times 0.5 \times 0.6\\=0.15

Putting values, we get,

w_A^2\sigma_A^2 +w_B^2\sigma_B^2 + 2w_Aw_BCov_{A,B}\\=(0.7)^2(0.5)^2 + (.3)^2(0.6)^2 + 2(0.7)(0.3)(0.15)\\=0.2179

Thus, the variance of the profile is 0.2179.

4 0
3 years ago
Jaun earns $11 per house and works at most $30 hours per week identify the independent and dependent quantity in this situation
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$11 is the independent and the $30 is dependent because to get the $30 a week, it depends on that $11 per house.
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