3 years ago

Find the area of a regular septagon (7 sided regular polygon) with side length 10.

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

A≈363.39
Your area is ^^

You might be interested in

Which of the following describes the diagonals of a square?

Feliz [49]

Answer:

ALL OF THE ANSWERS ARE CORRECT .

HOPE IT HELP YOU.

5 0

3 years ago

HURRY PLS

Dovator [93]

Y=2x-3 rise over run and then the y intercept

6 0

2 years ago

X^2+y^2-4x+2y=b <br>what is b?

Zina [86]

First of all youre not going to get a direct answer to all of these questions, youre going to have 3 finally equations(because thats the amount of variables you have).

8 0

4 years ago

Item 8

disa [49]

Answer:

452.39 mm^2

Step-by-step explanation:

Area of a circle = $\pi$ r^2

Here r = 12mm

Therefore, Area= $\pi$ x 12^2 = 452.389342...

Round to required degree of accuracy = 452.39mm^2

Hope this helps

8 0

3 years ago

Please help, thanks.

Liula [17]

Answer:

$\frac{ - 5}{54} + \frac{5 \times 6}{9 \times 6} = \frac{ - 5 + 30}{54} = \frac{25}{54}$

$\frac{15}{4} \div \frac{3}{8} = \frac{15}{4} \times \frac{8}{3} = 10$

$10 \times \frac{25}{54} = \frac{250}{54} = 4 \times \frac{17}{27}$

b )

$4 \times \frac{17}{27} = \frac{125}{27} =$

cube root =

$\frac{5}{3}$

c ) square root

$\frac{125}{27} = \frac{ \sqrt{25 \times 5} }{ \sqrt{3 \times 9} } = \frac{5 \sqrt{5} }{3 \sqrt{3} }$

3 0

3 years ago