2 years ago

Evaluate h(x) = -2x + 9 when x = -2,0, and 5.h(-2)=h(0) =h(5)=0

Mathematics

1 answer:

tatyana61 [14]2 years ago

6 0

Answer:

h(-2) = 13

h(0) = 9

h(5) = -1

Step-by-step explanation:

when h(-2)

h(-2) = -2*-2 + 9

h(-2) = 4 + 9

h(-2) = 13

when h(0)

h(0) = -2*0 + 9

h(0) = 9

when h(5)

h(5) = -2*5 + 9

h(5) = -10 + 9

h(5) = -1

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Evaluate h(x) = -2x + 9 when x = -2,0, and 5.h(-2)=h(0) =h(5)=0​

Evaluate h(x) = -2x + 9 when x = -2,0, and 5.h(-2)=h(0) =h(5)=0