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3 years ago

Output values below an amount

Computers and Technology

1 answer:

elena-s [515]3 years ago

5 0

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

for value in user_values:

if value < upper_threshold:

print(value)

def get_user_values():

n = int(input())

lst = []

for i in range(n):

lst.append(int(input()))

return lst

if __name__ == '__main__':

userValues = get_user_values()

upperThreshold = int(input())

output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

Explanation:

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Answer: See explanation

Explanation:

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2 years ago

What is the worst case running time of a linear search?

shtirl [24]

Answer:

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Explanation:

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The worst case scenario is when you find the value at the last array position. So, in a N-length array, the information is at position N. This means that the worst case running time of a linear search is O(N).

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3 years ago

Read 2 more answers

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Answer:

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3 years ago

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tatiyna

Answer:

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3 years ago

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def recursiveFactorial(number):

if number > 1:

return number * recursiveFactorial(number-1)

else:

return 1

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num = int(stringNum)

print(recursiveFactorial(num))

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2 years ago