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stepladder [879]
3 years ago
11

Below are 36 sorted ages of an acting award winner. Find Upper P70 using the method presented in the textbook.

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0

58 is your answer. hope it helps

Leona [35]3 years ago
6 0
The upper 70th percentile is the number below which 70% of the data lie.

The 70th percentile position is given by:

P_{70}= \frac{70N}{100} = \frac{70(36)}{100} =25.2

Thus, the 70th percentile position is approximately the 25th data item (after the data has been arranged in acsending order).

Given the following data:
<span>16 24 25 26 27 29 36 39 39 39 40 44 45 47 47 48 50 51 51 53 53 54 57 58
58 60 65 66 67 69 69 71 72 74 74 74

The 25th data in the data set is 58.

Therefore, the upper P70 is 58.
</span>
You might be interested in
Bananas are $.59 a pound what is the constant of proportionality
hichkok12 [17]
The constant proportionality is the proportionality of 59. Because it is the price, you just move the decimal point two places over to the left.
If you do this correctly you will get .59
4 0
3 years ago
If 18√8 - 8 √18 = √n, what is n?
Yuliya22 [10]

Answer:

n=288

Step-by-step explanation:

Rewrite the equation as  

√

n

=

18

√

8

−

8

√

18

.

√

n

=

18

√

8

−

8

√

18

To remove the radical on the left side of the equation, square both sides of the equation.

√n

2

=

(

18

√

8

−

8

√

18

)

2

Simplify each side of the equation.  

Use  

n

√

a

x

=

a

x

n

to rewrite  

√

n  as  n

1

2

.

(

n

1

2

)

2

=

(

18

√

8

−

8

√

18

)

2

Simplify  

(

n

1

2

)

2

.  

Multiply the exponents in  

(

n

1

2

)

2

.  

Apply the power rule and multiply exponents,  

(

a

m)n

=

a

m

n

.

n

1

2

⋅

2

=

(

18

√

8

−

8

√

18

)

2

Cancel the common factor of  2  

Cancel the common factor.

n

1

2

⋅

2

=

(

18

√

8

−

8

√

18

)

2

Rewrite the expression.

n

1

=

(

18

√

8

−

8

√

18

)

2

Simplify.

n

=

(

18

√

8

−

8

√

18

)

2

Simplify  

(

18

√

8

−

8

√

18

)

2

Simplify each term.

Rewrite  

8  as  2

2

⋅

2

.  

Factor  

4  out of  8  

n

=

(

18

√

4

(

2

)

−

8

√

18

)

2

Rewrite  

4  as  2

2  

n

=

(

18√

2

2

2

−

8

√

18

)

2

Pull terms out from under the radical.

n

=

(

18

(

2

√

2

)

−

8

√

18

)

2

Multiply  

2  by  18  

n

=

(

36

√

2

−

8

√

18

)

2

Rewrite  

18

as  

3

2

⋅

2

.

Factor  

9

out of  

18

.

n

=

(

36

√

2

−

8

√

9

(

2

)

)

2

Rewrite  

9

as  

3

2

.

n

=

(

36

√

2

−

8

√

3

2

⋅

2

)

2

Pull terms out from under the radical.

n

=

(

36

√

2

−

8

(

3

√

2

)

)

2

Multiply  

3

by  

−

8

.

n

=

(

36

√

2

−

24

√

2

)

2

Simplify terms.

Subtract  

24

√

2

from  

36

√

2

.

n

=

(

12

√

2

)

2

Simplify the expression.

Apply the product rule to  

12

√

2

.

n

=

12

2

√

2

2

Raise  

12

to the power of  

2

.

n

=

144

√

2

2

Rewrite  

√

2

2

as  

2

.

Use  

n

√

a

x

=

a

x

n

to rewrite  

√

2

as  

2

1

2

.

n

=

144

(

2

1

2

)

2

Apply the power rule and multiply exponents,  

(

a

m

)

n

=

a

m

n

.

n

=

144

⋅

2

1

2

⋅

2

Combine  

1

2

and  

2

.

n

=

144

⋅

2

2

2

Cancel the common factor of  

2

.

Cancel the common factor.

n

=

144

⋅

2

2

2

Rewrite the expression.

n

=

144

⋅

2

1

Evaluate the exponent.

n

=

144

⋅

2

Multiply  

144

by  

2

.

n

=

288

5 0
3 years ago
It wants me to find the volume of the cylinder
hodyreva [135]
<h3>volume =603.19 cm cube</h3>
6 0
3 years ago
A) What is the domain and range of the graph? (Use the equations editor or explain)
riadik2000 [5.3K]

The domain: -5 < x ≤ 1 and the range: -3 ≤ y ≤ 1 is a function. b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

<h3>What is the domain and range of the function?</h3>

The domain of a function is defined as the set of all the possible input values that are valid for the given function.

The range of a function is defined as the set of all the possible output values that are valid for the given function.

The domain of a relation is the set of values of the independent variable for a defined function.

The domain is the horizontal extent of the graph.

The range of a relation is the set of values of the dependent variable for a defined function.

The range is the vertical extent of the graph.

The vertical line can intersect the graph in at most one place.

a)

This graph extends from x > -5 to x = 1.

The domain

 -5 < x ≤ 1   ------   (-5, 1] in interval notation

This graph extends from y = -3 to y = 1.

The left side of the graph does not include the point (-5, 1), but the right side includes the point (1, 1).

y = 1 is one of the output values of the relation.

The range

 -3 ≤ y ≤ 1 . . . . . . . . [-3, 1] in interval notation

b)

No, the vertical line crosses the graph in more than one place, therefore, the relation shown is a function.

Learn more about the domain and range of the function:

brainly.com/question/2264373

#SPJ1

8 0
2 years ago
Using the graph, predict how many people will be needed to eat 300 pounds of meal?​
kkurt [141]

Answer:

100 people

Step-by-step explanation:

if u notice the points are (2,6) and (6,18). 6÷2=3 and 18÷6=3, so if you catch this pattern than you can do 300÷3=100

8 0
3 years ago
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