Apply the negative exponent rule, so move the expression to the denominator to make the exponents positive.
Your answer is:
1
--------------
r^7 + s^12
15)
20/8 = x / 6
x = 20 * 6 / 8
x = 15
16)
18/54 = (x+4)/75
1/3 = (x+4) / 75
3(x+4) = 75
3x + 12 = 75
3x = 63
x = 21
SF = 54/18
SF = 3
17)
complement angles sum = 90
90 /18 = 5
so
5 x 11 = 55
5 x 7 = 35
smaller angle = 35 degrees
18)
ratio 4:5:9
4+5+9 = 18
sum of interior angles of a triangle = 180
180 / 18 = 10
largest angle = 10 x 9 = 90
answer
largest angle = 90 degrees
Remark
You are using the midpoint formula. Instead of finding the midpoint, you are looking for one of the points, so you have to rearrange the formula a little bit.
Givens
Midpoint (4,2)
One endpoint (6,1)
Object
Find the other endpoint.
Formula
m(x,y) = (x1 + x2)/2, (y1 + y2)/2)
Solution
Find the x value
4 = (6 + x2)/2 Multiply both sides by 2
4*2 = 6 + x2 Subtract 6 from both sides.
8 - 6 = x2
x2 = 2
Find the y value
2 = (1 + y2)/2 Multiply by 2
4 = 1 + y2 Subtract 1 from both sides.
4 - 1 = y2
y2 = 3
Conclusion
R(x,y) = (2,3)
Answer:
150
im pretty sure thats right
Answer:


Step-by-step explanation:
Given
See attachment for complete question
Solving (a): The entry C22
First, matrix C represents the inventory at the end of July.
The entry of C is calculated as:

i.e.
![C = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right] - \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543%26356%26643%5C%5C364%26476%26419%5C%5C376%26903%26409%5Cend%7Barray%7D%5Cright%5D%20%20-%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D102%2678%2697%5C%5C98%2687%2659%5C%5C54%2689%2679%5Cend%7Barray%7D%5Cright%5D)
![C = \left[\begin{array}{ccc}543-102&356-78&643-97\\364-98&476-87&419-59\\376-54&903-89&409-79\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543-102%26356-78%26643-97%5C%5C364-98%26476-87%26419-59%5C%5C376-54%26903-89%26409-79%5Cend%7Barray%7D%5Cright%5D)
![C = \left[\begin{array}{ccc}441&278&546\\266&389&360\\322&814&330\end{array}\right]](https://tex.z-dn.net/?f=C%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D441%26278%26546%5C%5C266%26389%26360%5C%5C322%26814%26330%5Cend%7Barray%7D%5Cright%5D)
Item C22 means the entry at the second row and the second column.
From the matrix

Solving (b): The maximum A31 possible.
From the given data, we have:
![Inventory = \left[\begin{array}{ccc}543&356&643\\364&476&419\\376&903&409\end{array}\right]](https://tex.z-dn.net/?f=Inventory%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D543%26356%26643%5C%5C364%26476%26419%5C%5C376%26903%26409%5Cend%7Barray%7D%5Cright%5D)
![Unit\ Sales = \left[\begin{array}{ccc}102&78&97\\98&87&59\\54&89&79\end{array}\right]](https://tex.z-dn.net/?f=Unit%5C%20Sales%20%3D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D102%2678%2697%5C%5C98%2687%2659%5C%5C54%2689%2679%5Cend%7Barray%7D%5Cright%5D)
From the matrices above.
A31 means entry at the 3rd row and 1st column.
So, the possible values of A31 are:

and

By comparison, 376 > 54
So: