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8_murik_8 [283]
3 years ago
7

A set has 127 proper subsets. how many elements are in the set?

Mathematics
1 answer:
Mama L [17]3 years ago
8 0
The set has 7 elements
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Simon leans a 20 ft ladder against the side of his house so that the base of the ladder is
finlep [7]
The answer is 19.4
Most of the time when you try to find a missing length of a right triangle you use Pythagorean theorem. Pythagorean theorem is A squared plus B squared equals C squared. C squared is always going to be the longest length/diagonal line otherwise known as your hypotenuse. In this case the ladder is the hypotenuse. So instead of adding five squared +20 squared you’re going to square 20 and then subtract five squared to get the missing length which would be B squared and then you have to find the square root of B squared. So 20 squared is 4000. 5squared is 25 400-25 = 375 square root of 375 is about 19.4.

7 0
3 years ago
. 7/8 = /48<br> A. 6<br> B. 1<br> C. 13<br> D. 42
hodyreva [135]
 7/8=x/48

x=(7/8)48
x=(7)(48/8)
x=(7)(6)
x=42
                D.42

4 0
3 years ago
75% of the children at Fisher Elementary walk to school. If there are 200 students at Fisher Elementary, how many walk to school
BlackZzzverrR [31]

Answer: 150 students walk to school

Step-by-step explanation: 75%=0.75

200 multiplied by 0.75

 200×0.75=150 students

            Or

75%=3/4

3/4 of the children walk to school

3/4×200=3/4×200/1=150

4 0
3 years ago
In the derivation of Newton’s method, to determine the formula for xi+1, the function f(x) is approximated using a first-order T
dimaraw [331]

Answer:

Part A.

Let f(x) = 0;

suppose x= a+h

such that f(x) =f(a+h) = 0

By second order Taylor approximation, we get

f(a) + hf'±(a) + \frac{h^{2} }{2!}f''(a) = 0

h = \frac{-f'(a) }{f''(a)} ± \frac{\sqrt[]{(f'(a))^{2}-2f(a)f''(a) } }{f''(a)}

So, we get the succeeding equation for Newton's method as

x_{i+1} = x_{i} + \frac{1}{f''x_{i}}  [-f'(x_{i}) ± \sqrt{f(x_{i})^{2}-2fx_{i}f''x_{i} } ]

Part B.

It is evident that Newton's method fails in two cases, as:

1.  if f''(x) = 0

2. if f'(x)² is less than 2f(x)f''(x)    

Part C.

In case  x_{i+1} is close to x_{i}, the choice that shouldbe made instead of ± in part A is:

f'(x) = \sqrt{f'(x)^{2} - 2f(x)f''(x)}  ⇔ x_{i+1} = x_{i}

Part D.

As given x_{i+1} = x_{i} = h

or                 h = x_{i+1} - x_{i}

We get,

f(a) + hf'(a) +(h²/2)f''(a) = 0

or h² = -hf(a)/f'(a)

Also,             (x_{i+1}-x_{i})² = -(x_{i+1}-x_{i})(f(x_{i})/f'(x_{i}))

So,                f(a) + hf'(a) - (f''(a)/2)(hf(a)/f'(a)) = 0

It becomes   h = -f(a)/f'(a) + (h/2)[f''(a)f(a)/(f(a))²]

Also,             x_{i+1} = x_{i} -f(x_{i})/f'(x_{i}) + [(x_{i+1} - x_{i})f''(x_{i})f(x_{i})]/[2(f'(x_{i}))²]

6 0
3 years ago
To describe a specific arith-
Bezzdna [24]

Answer:

f(x) = 7x + 30

Step-by-step explanation:

We need at least two points to write the equation of a straight line.

The recursive formula that Elijah wrote is:

f(0) = 30

f(n + 1) = f(n) + 7

When we substitute n=0, we get:

f(0 + 1) = f(0) + 7

f(1) = 30 + 7

f(1) = 37

The points (0,30) and (1,37) lies on this line.

The equation of this line is of the form:

f(x) = mx + b

where b =30 is the y-intercept and m=7 is the slope.

We plug in these values to get:

f(x) = 7x + 30

Note that the slope of the line is equal to the common difference of the Arithmetic Sequence.

You could also use the two points to find the slope:

m =  \frac{37 - 30}{1 - 0}  = 7

4 0
3 years ago
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