Show that 6 – 4x - x^2 can never be greater than 10. ( This is an Additional Math Question )
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given
6 - 4x - x²
Since the coefficient of the x² term < 0 then parabola has a maximum vertex.
To find the x- coordinate of the vertex
= -
with a = - 1 and b = - 4 , then
= -
= - 2
The corresponding y- coordinate is found by substituting x = - 2 , that is
6 - 4(- 2) - (- 2)² = 6 + 8 - 4 = 10
vertex = (- 2, 10 )
The maximum value of the function is the y- coordinate of the vertex
Then maximum value is 10
Thus 6 - 4x - x² is never greater than 10
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<h2><u>Solution (1)</u> :</h2>
Given, to find A we have to :
- square m
- Add y to m²
- Subtract 7 from m² + y
From the question, the following equation can be formed :
Therefore, the formula for finding A = m² + y - 7
<h2><u>Solution (2)</u> :</h2>The value of A we can derive from the formula is :
Value of m = 3 (given)
Which means :
Thus, the value of A = 2+y
Therefore, the value of A = <u>2+y</u>