Hey there :)
Now lets name each house
A B C D E F
500ft <-> 500ft <-> 500ft <-> 500ft <-> 500ft <-> 2000ft
Let's say the bus stops at A
= 0 ( from A ) + 500 ( from B ) + 500 + 500 ( from C ) + 500 + 500 + 500 ( from D ) + 500 + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 500 + 2000 ( from F )
= 0 + 500 + 1000 + 1500 + 2000 + 4000
= 9000 ft
at B
= 500 ( from A ) + 0 ( from B ) + 500 ( from C ) + 500 + 500 ( from D ) + 500 + 500 + 500 ( from E ) + 500 + 500 + 500 + 2000 ( from F )
= 500 + 0 + 500 + 1000 + 1500 + 3500
= 7000 ft
at C
= 500 ( from A ) + 500 + 500 ( from B ) + 0 ( from C ) + 500 ( from D ) + 500 + 500 ( from E ) + 500 + 500 + 2000 ( from F )
= 500 + 1000 + 0 + 500 + 1000 + 3000
= 6000 ft
Do the same for D , E and F
at D
= 6000 ft
at E
= 7000 ft
at F
= 15000 ft
You will find that the bus should stop at either C or D to make the sum of distances from every house to the stop as small as possible.
Answer:
Inertia is a tendency to do nothing or to remain unchanged.
It is a property of matter by which it continues in its existing state of rest or uniform motion in a straight line unless that state is changed by an external force.
Answer:
The answer would be A. 1.25
Answer:
6. SAS Postulate
5. ASA Postulate
Step-by-step explanation:
Answer:
Step-by-step explanation:
se the graph to determine the input values that
correspond with f(x) = 1.
O x=4
O x= 1 and x = 4
O x= -7 and x = 4
O x= -7 and x = 2
6.
(-6, 4)
4
(1,4)
w
2
(-7, 1)
(2, 1) x
2
4
-8/ -6 -4 -2
-2
-4