An object sits at the edge of a table top with a mass of 180 kg. It is connected by a magical physics thread to a mass of 250 kg
via a pulley which is hanging in the air below the edge of the table top. There is an unknown amount of friction between the 180 kg mass and the table. The entire thing is accelerating at 2 m/s/s towards the edge of the table (250 kg mass is moving down).
What is the force of friction?
What is the coefficient of friction?
What is the force of friction?
What is the coefficient of friction?
1 answer:
Answer:
Force of Friction = 1640 N
Coefficient of friction = 0.911
Explanation:
forces act on the objects as shown in the graph.
Fx=Foroce of friction
T=tension of the thread
R=Normal Force(R=1800N)
μ= friction coefficient
a=acceleration =
applying F=ma to 250kg object downwards
applying F=ma to 180kg object rightwards
According to Frictional Force Formula,
μ*R
1640=μ*1800
μ=0.911
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Answer:
(a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.
Explanation:
Given that,
Charge = 10.1 μC
Capacitor C₁ = 1.10 μF
Capacitor C₂ = 1.92 μF
Capacitor C₃ = 1.10 μF
Potential V₁ = 51.5 V
Let V₁ and V₂ be the potentials on the two plates of the capacitor.
(a). We need to calculate the potential on the negative plate of the 1.10 μF capacitor
Using formula of potential difference
Put the value into the formula
The potential on the second plate
(b). We need to calculate the equivalent capacitance of the two capacitors
Using formula of equivalent capacitance
Put the value into the formula
Hence, (a). The potential on the negative plate is 42.32 V.
(b). The equivalent capacitance of the two capacitors is 0.69 μF.
Explanation:
you can see this example to undersranding the question
