Answer:
The total amount of water that enters the tank is:
250 gal/min + 100 gal/min = 350gal/min.
Then, if the level of the water remains constant, this means that the water leaves the tank at a rate of 350gal/min.
We know that the diameter of the pipe is 8 inches, then the area of the pipe is:
A = pi*(d/2)^2 = 3.14*(4in)^2 = 50.24in^2
now, the flow can be calculated as:
Q = v*A = (velocity*area)
if we want to write our velocity in inches per minute, then we need to write the entering flow in cubic inches:
1 gallon = 231 in^3
then:
350gal/min = (350*231) in^3/min = 80,850 in^3/min.
Then the water that leaves the tank must be the same amoun, we have:
Q = 80,850 in^3/min. = v*A = v*50.24in^2
v = (80,850in^3/min)/50.24in^2 = 1609.3 in/min.
The velocity of the flow leaving the tank is 1609.3 in/min.
