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3 years ago

How many moles are in 95 g of Na?

2 answers:

7 0

To convert grams to moles for Na you take the amount given (95 grams) and divide it by the molar mass of the element. (molar mass of Na is 22.9898) and that's how you get the number of moles (4.13)

nexus9112 [7]3 years ago

3 0

1.8 mol of Na. hope this helps

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What would happen if I removed the battery from the circuit?

ira [324]

Answer:

The current would stop

Explanation:

Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.

3 0

3 years ago

In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6

stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

r₂= 7.5 cm

head upto water level is to rise = 60 + 5

= 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q

π r₁² v₁ = π r₂² v₂ = 0.015

$v_1= \dfrac{r_2^2}{r_1^2} v_2$

$v_1= \dfrac{7.5^2}{5^2} v_2$

$v_1= 2.25 v_2$

$v_2 = \dfrac{0.015}{\pi r_2^2}$

$v_2 = \dfrac{0.015}{\pi 0.075^2}$

v₂ = 0.848 m/s

v₁ = 1.908 m/s

Applying Bernoulli's equation

$P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h$

$P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65$

$P_p= 635539.32 Pa$

P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0

3 years ago

Two students have fitted their scooters with the same engine. Student A and his

sammy [17]

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

m is mass
a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

3 0

2 years ago

We place a small pressure sensor at a certain depth in water. with which orientation does the sensor register the greatest press

Dominik [7]

Hydrostatic pressure is independent of directions.

7 0

3 years ago

A long line carrying a uniform linear charge density+50.0μC/m runs parallel to and 10.0cm from the surface of a large, flat plas

IRISSAK [1]

Answer:

The location of the points is at the distance above the line charge Option A.

Explanation:

Part A

The electric field due to a line of charge is expressed as :

Eₐ = λ /2πε₀L …… (1)

while the electric field due to a non-conducting elastic sheet is expressed as:

Еₙ = λ /2ε₀ …… (2)

In order for the particle to experience no force, the electric field at that point is zero.

Equating (1) and (2) together, we have:.

λ /2πε₀L = σ /2ε₀

Rearranging the above expression, we have:

L = λ /πσ

Substituting 50.0 μC/m for λ, 3.14 for π , and 100 μC/ m² for σ, we have:

L= 50.0 μC/m / (3.14)* 100 μC/ m²

L = 0.159m

From the L value obtained above, the location of all points where an particle would experience no force due to the arrangement of charged objects is L 0.159m from the line.

Part B

The electric field is zero at all the points above the line with the distance 0.159m from the line.

Thus, the location of the points is at the distance above the line charge Option A.

6 0

3 years ago