Ask question

Ask question

All categories

3 years ago

13

yo this is due tomorrow help ya girl out : if a 2kg mass is accelerating at a rate of 2m/s^2 on a frictionless surface. how much

force is acting on the mass?

1 answer:

krok68 [10]3 years ago

8 0

We Know, F = m.a
Here, m = 2 Kg
& a = 2 m/s²

Substitute for it,
F = 2*2 Kgm/s²
F = 4 Kgm/s²

You might be interested in

An object, initially at rest moves 250m in 17s. What is it's acceleration?

Gekata [30.6K]

With the values you've given, only velocity can be found.
Acceleration is rate of change of velocity

d= 250s
t= 17s

a= d/t
= $\frac{250}{17}$
= 4.7 $\frac{m}{s}$

8 0

2 years ago

On which planet would your weight be the most and the least?

hoa [83]

Answer:

Jupiter and neptune

Explanation:

6 0

2 years ago

What happens to the strength of the magnetic field as you come closer to the current carrying wire

Leokris [45]

Form concentric circles around the wire

6 0

3 years ago

The force required to stretch a Hooke’s-law

Setler [38]

I think this is correct, but I am not entirely certain.

Find the force constant of the spring:

F = - KX

(0 - 62.4) = -K(0.172m)

-362.791 = -K

362.791 N/m = K

Find the work done in stretching the spring:

W = (1/2)KX

W = (1/2)(362.791)(0.172m)

W = 31.2 J

5 0

2 years ago

A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−

Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ .

Explanation:

Given that,

The actual wavelength of the hydrogen atom, $\lambda_a=5.13\times 10^{-7}\ m$

A hydrogen atom in a galaxy moving with a speed of, $v=6.65\times 10^6\ m/s$

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

$v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}$

$\lambda_o$ is the observed wavelength

$\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m$

So, the observed wavelength on Earth from that hydrogen atom is $5.24\times 10^{-7}\ m$ . Hence, this is the required solution.

8 0

2 years ago