The force of gravity between two objects is increased when the mass of objects is increased.
Answer:
Explanation:
given,
initial speed of the shot = 12.0 m/s
angle = 40°
height at which shot leaves her hand = 1.80 m
v_x = 12 cos 40° = 9.19 m/s
v_y = 12 sin 40° = 7.71 m/s
time to reach maximum height =
= 
= 
= 0.787 s
h = 7.71 × 0.787 - 0.5 × 9.81 × 0.787²
h = 3.03 m
the maximum height attain = 3.03 + 1.8 = 4.83 m
now free fall from the maximum height
t = 0.9928 s
total time = 0.9928 + 0.787 = 1.7798 s
range =
d = vₓ t
d = 16.36 m
Answer:
Answer in Explanation
Explanation:
Whenever we talk about the gravitational potential energy, it means the energy stored in a body due to its position in the gravitational field. Now, we know that in the gravitational field the work is only done when the body moves vertically. If the body moves horizontally on the same surface in the Earth's Gravitational Field, then the work done on the body is considered to be zero. Hence, the work done or the energy stored in the object while in the gravitational field is only possible if it moves vertically. This vertical distance is referred to as height. <u>This is the main reason why we require height in the P.E formula and calculations.</u>
The derivation of this formula is as follows:
Work = Force * Displacement
For gravitational potential energy:
Work = P.E
Force = Weight = mg
Displacement = Vertical Displacement = Height = h
Therefore,
P.E = mgh
Answer:
The work done is L= 49.83 Joules
Explanation:
m= 2.44kg
d= 1.55m
α= 69.6°
g= 9.8 m/s²
μ= 0.691
F= ?
Fy= F*sin(α)
Fx= F*cos(α)
Fr= μ * Fx
Fr= μ * F*cos(α)
W= m*g
W= 23.91 N
Fy - W - Fr = 0
F*sin(α) - W - μ * F*cos(α) = 0
F* ( sin(α) - μ *cos(α) ) = W
F= W / ( sin(α) - μ *cos(α) )
F= 34.3 N
L= Fy * d
L= 49.83 J
Sum of all forces = mass * acceleration
Ft= tension force
Fw= force of gravity (Fw= mass* acceleration of gravity which is 9.8 this only applies to force of gravity)
Ft- Fw = 0 (there is no acceleration)
Ft = Fw
Ft= m*g
Ft= 0.250kg*9.8m/s
Ft= 2.45N
