3 years ago

Is it possible for a triangle to have sides with given lengths? 5 inches, 8 inches, 15 inches

Mathematics

1 answer:

Tema [17]3 years ago

8 0

Yes it is possible indeed

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Answer: $\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

Step-by-step explanation:

$c=24x^2 pi$

Switch sides:

$24x^2\pi =Kc$

divide both sides by $24\pi$

$\frac{24x^2\pi }{24\pi }=\frac{Kc}{24\pi }$

simplify:

$x^2=\frac{Kc}{24\pi }$

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answer: $x=\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi },\:x=-\frac{\sqrt{6}\sqrt{\pi }\sqrt{Kc}}{12\pi }$

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3 years ago

Evaluate -2x + -3y if x = 10 and y = -6

emmasim [6.3K]

-2(10)+-3(-6)

It would be -2

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3 years ago

Not sure what to do..

kompoz [17]

Answer:

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Step-by-step explanation:

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