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3 years ago

Solve this inequality j/4-8<4

2 answers:

5 0

First, you need to have j on it own. Since j is over 4-8, you times both sides of the inequality so the /4-8 is canceled.

Your new inequality equation is j<4(4-8). Solve the bracket and then times the answer by 4.

~ j<4(-4)

~ j<-16

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Ainat [17]3 years ago

4 0

Answer is 12 I think

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HELP PLEASE ASAP!!! 50 points

neonofarm [45]

Answer:

(a+b,c)

Step-by-step explanation:

Note that the midpoint formula is:

$(\frac{x_{1} +x_{2}}{2}, \frac{y_{1} +y_{2}}{2})$

Point A (0,0) and Point C (2a+2b,2c)

It follows that:

$(\frac{(2a+2b +0}{2}, \frac{2c+0}{2})\\(\frac{(2(a+b)}{2}, \frac{2c}{2})\\\\(a+b,c)$

3 0

3 years ago

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in an isosceles triangle the base angle are equal and the vertex is 80 degree find the measurement of the base angle

Oliga [24]

Answer:

50 each base angle

Base Angle_1 + Base Angle_2 + Vertex = 180

50 + 50 + 80 = 180

180 = 180

Step-by-step explanation:

Sum of interior angles of Triangle is 18- degrees.

2b + vertex = 180

2b + 80 = 180

2b + 80 -80 = 180 - 80

2b = 100

b = 50

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2 years ago

What is 60 out of 70 as a percentage?

bearhunter [10]

60 divided by 70 and multiplied by 100 to get your answer

6 0

3 years ago

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Use the drawing tool(s) to form the correct answer on the provided graph. Graph the solution to this system of inequalities in t

Leya [2.2K]

The solution to the system of inequalities is (-3.375, 1.75)

<h3>How to graph the inequalities?</h3>

The system of inequalities is given as:

3y > 2x+12

2x+y < -5

Next, we plot the graph of the system using a graphing tool

From the graph, both inequalities intersect at

(-3.375, 1.75)

Hence, the solution to the system of inequalities is (-3.375, 1.75)

Read more about system of inequalities at:

brainly.com/question/19526736

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2 years ago

A Social welfare association decides to supply drinking water for the flood affected people. The drinking water is filled in a c

pickupchik [31]

Answer:

1,499 liter

Step-by-step explanation:

The rest of the question is:

each is in the shape of a cylinder of radius 21 cm and height is 50 cm.

==============================================================

The quantity of water left in the tanker after distribution

= Total quantity - Distributed quantity

Total quantity = Volume of the giving figure

= Volume of the cylinder + volume of 2 hemispheres

Volume of the cylinder of 4.2 m length and 1.2 m of a diameter.

L = 4.2 and radius = r = 0.5 * diameter = 0.5 * 1.2 = 0.6

Volume of cylinder = π r² L = (22/7) * 0.6² * 4.2 = 4.752 m³

Volume of 2 hemispheres = 2*0.5 * (4/3) π r³ = (4/3) * (22/7) * 0.6³

=792/875 m³

Total volume = 4.752 + 792/875 = 198/35 ≈ 5.657 m³

Distributed quantity = 60 times the volume of a cylinder of radius 21 cm and height is 50 cm

Distributed quantity = 60 * π r² L = 60 * (22/7) * 21² * 50 = 4,158,000 cm³

Since 1 m³= 1,000,000 cm³

Distributed quantity = 4,158,000 cm³ = 4.158 m³

The quantity of water left in the tanker after distribution =

= 198/35 - 4.158 ≈ 1.499 m³

Since 1 m³= 1,000 liter

The quantity of water left in the tanker after distribution =

= 1.499 m³ = 1.499 * 1000 = 1,499 liter

7 0

3 years ago

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