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kotykmax [81]
3 years ago
8

Unit 2:logic&proof homework 1: inductive reasoning

Mathematics
1 answer:
Vikentia [17]3 years ago
5 0
I’m not sure i understand what you are asking
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Determine whether each set of numbers can be the measures of the sides of a triangle. If so, classify the triangle as acute, obt
IgorLugansk [536]

9514 1404 393

Answer:

  obtuse triangle

Step-by-step explanation:

The two shortest sides are 7, 15. Their sum is 7+15 = 22, which is longer than the longest side, so these lengths will form a triangle.

__

The "form factor" can be computed to be ...

  a^2 +b^2 -c^2 . . . . . where c = longest side

This value is ...

  7^2 +15^2 -21^2 = 49 +221 -441 = -167

This negative value indicates the largest angle is more than 90°, so the triangle is obtuse.

_____

<em>Additional comment</em>

This "form factor" has the same sign as the cosine of the largest angle. The cosine is negative for angles greater than 90°. The cosine of the angle is ...

  "form factor"/(2ab) = -167/210

  largest angle = arccos(-167/210) ≈ 142.678°

3 0
3 years ago
What is the value of 7 in the number 21,780​
Sergio [31]

1111111111111111111111111111111111111111111111111

8 0
2 years ago
Determine whether the statement below is true or false diam is a rhombus
Marat540 [252]

Answer:

true

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A spherical iron ball 10 in. in diameter is coated with a layer of ice of uniform thickness. If the ice melts at a rate of 15 St
seraphim [82]

Answer:

a) Rate at which the thickness of the ice is decreasing, da/dt = -0.024 in/min

b) Rate at which the outer surface area is decreasing, dA/da = -4.22 in²/min

Step-by-step explanation:

The volume of the sphere, V = 4/3 πr³

The thickness of the ice = a

inner diameter = 10  in

inner radius = 10/2 = 5 in

outer radius = 5 + a

Therefore, volume of ice = volume of the outer radius - volume of the inner radius

V = 4/3 π (4+a)³ - 4/3 π4³

V = 4/3 π ( 4³ + 12a² + 48a + a³ -4³)

V = 4/3 π(a³ + 12a² + 48a)

dV/dt = 4/3 π (3a²da/dt + 24ada/dt + 48da/dt)

dV/dt = 4π(a²da/dt + 8ada/dt + 16da/dt)..............(1)

When a = 3 in, dV/dt = -15 m³/min

Substitute these values into equation (1)

-15 = 4π(9da/dt + 24 da/dt + 16da/dt)

-15/4π = 49da/dt

-1.194 = 49da/dt

da/dt = -1.194/49

da/dt = -0.024 in/min

b) How fast is the outer surface area of ice decreasing

The area of a sphere, A = 4πr²

The outer surface area of the sphere, A = 4π(4+a)²

dA/da = 8π (4+a) da/dt

a = 3 in, da/dt = -0.024 in/min

dA/da = 8π(4+3)*(-0.024)

dA/da = -4.22 in²/min

8 0
3 years ago
Find the area of a square with the coordinates (-4,3),(-2,8)(3,6)(1,1)
Leto [7]
If this is graphing you have to graph it first to find the area. 
3 0
4 years ago
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