if the ellipse has a major axis of 12 inches, that means its major radius is half that, or 6, and if its minor axis is 7, then its minor radius is half that, 3.5.
![\bf \textit{volume of an elliptical cylinder}\\\\ V=\pi ab h~~ \begin{cases} a=\textit{major axis radius}\\ b=\textit{minor axis radius}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=3.5\\ h=21 \end{cases} \\\\\\ V=\pi (6)(3.5)(21)\implies V\approx 1385.44236023309881816203](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20an%20elliptical%20cylinder%7D%5C%5C%5C%5C%0AV%3D%5Cpi%20ab%20h~~%0A%5Cbegin%7Bcases%7D%0Aa%3D%5Ctextit%7Bmajor%20axis%20radius%7D%5C%5C%0Ab%3D%5Ctextit%7Bminor%20axis%20radius%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D3.5%5C%5C%0Ah%3D21%0A%5Cend%7Bcases%7D%0A%5C%5C%5C%5C%5C%5C%0AV%3D%5Cpi%20%286%29%283.5%29%2821%29%5Cimplies%20V%5Capprox%201385.44236023309881816203)
Answer:
<h3>i hope it's helpful for you</h3>
Answer:
5 cubes
Step-by-step explanation:
The volume of a square pyramid is given in terms of its side length (s) and height (h) as ...
V = (1/3)s^2·h
For the given measurements, the volume is ...
V = (1/3)(9 cm)^2 ·(10 cm) = 270 cm^3
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The volume of each cube of wax is the product of its length, width, and height, so is ...
V = (4 cm)^3 = 64 cm^3
___
Then the number of wax cubes required to fill the pyramid is ...
(270 cm^3)/(64 cm^3/cube) = 4 7/32 cubes
Four cubes are not quite enough to make the candle.
Devin will need 5 cubes to make the candle.
A possible sizes two teams of 9 or 9 teams of 2, 6 teams of 3 or 3 teams of 6
B yes 3 lanes could divide her 18 students by putting 6 people in each lane
18/3= 6
