Answer:
The maximum area is 
Step-by-step explanation:
Let
x----> the length of rectangle
y---> the width of rectangle
we know that
The perimeter of rectangle is equal to

we have

so


------> equation A
Remember that
The area of rectangle is equal to
-----> equation B
substitute equation A in equation B

This is a vertical parabola open downward
The vertex is a maximum
The y-coordinate of the vertex of the graph is the maximum area of the garden and the x-coordinate is the length for the maximum area
using a graphing tool
The vertex is the point 
see the attached figure
Find the value of y
-----> 
The dimensions of the rectangular garden is
by 
For a maximum area the garden is a square
The maximum area is 
Answer:
∠NQP = 74°
Step-by-step explanation:
NPQ is a triangle.
We know the sum of 3 angles of a triangle is 180 degrees. So we can write:
N + P + Q = 180
2x + 34 + 2x + 2 = 180
Now, we can solve for x:

The measure of NQP is "2x+2", we plug in x = 36, and find the measure of NQP:
∠NQP = 2(36) + 2 = 74°
Answer:
the desired equation is y = 3^x
Step-by-step explanation:
if x = 2, then y = 9, and 9 is 3². If x = 4, y = 81 = 3^4.
Therefore we can conclude that the desired equation is y = 3^x