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tresset_1 [31]
3 years ago
9

Please help !!!!! Urgent !!!

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
I suppose the answer would be 3n-2N can be no greater than 4
If I’m wrong feel free to correct me
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30. While making a dessert, Jane used
antiseptic1488 [7]

Answer:

Jane used 2/5 of a scoop more of brown sugar than she did with white sugar.

Step-by-step explanation:

If you want to find how much more something is from something else, you subtract. So, subtract 9/10-1/2. If you want to subtract, they should both have the same denominator. So, 9/10-1/2 is the same as 9/10-5/10. 9/10-5/10 is equal to 4/10 which is simplified to 2/5.

4 0
3 years ago
Can someone please help me!
Contact [7]
With what? I don't see a question
8 0
4 years ago
Read 2 more answers
How long will u have to wait for the bus?
geniusboy [140]
11 mins

5:00
5:12
5:24
5:36
5:48
6:00

so the minutes go up in 12s meaning that their will be a bus at 7 and 8 so then you can work out

8:00
8:12
8:24
8:36
8:48

and 8:48 - 8:37 = 11 minutes waiting time
8 0
3 years ago
Read 2 more answers
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
4 years ago
Read 2 more answers
Anybody know the answer???
igomit [66]
The sum of the two sides of the triangle must be greater than the third side, so 

5<x<41 is the answer
8 0
3 years ago
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