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Slav-nsk [51]
3 years ago
6

Maria said," The 4 in 400,000 has a value of 400

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0
Maria said," The 4 in 400,000 has a value of 400 THOUSANDS
the 4 has a value of four hundred thousands
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How to find restrictions for x??<br> 3. F(x)=2 sqrt x-4
stealth61 [152]

Answer:

  1. none
  2. none
  3. x ≥ 4

Step-by-step explanation:

The restrictions placed on the independent variable in a function are those necessary to ensure that the function is defined for all allowed values of that variable.

In the graphs of problems 1) and 2), we see that the functions are defined for all values of x, so there are no restrictions.

__

3. For the function ...

  f(x)=2\sqrt{x-4}

the value under the radical cannot be negative. The square root function is not defined for negative values, so the restriction is ...

  x -4 ≥ 0

  x ≥ 4 . . . . . . . add 4 to both sides of the inequality

4 0
3 years ago
When f(n) = 34, what is the value of f(n-6)?
Mashutka [201]

Answer:

28

Step-by-step explanation:

f(n)=34, f(n-6)=34-6

=28

3 0
3 years ago
What is the answer for this​
jek_recluse [69]

Answer:

Step-by-step explanation:

.72x+3=0.3(2.4+15)

.72x+3=0.72+4.5=0.72+4.50

.72 x=5.22

x=\frac{5.22}{0.72} =\frac{522}{72} =\frac{29}{4} =7\frac{1}{4}

4 0
3 years ago
I need help ASAP !!!
lbvjy [14]
The answer is (x,y) —> (y,-x)
8 0
4 years ago
A past survey of students taking a standardized test revealed that ​% of the students were planning on studying engineering in c
Angelina_Jolie [31]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

The  95% confidence interval is  -0.00870

Step-by-step explanation:

From the question we are told that

     The first sample  size  is  n_1  =  1068000

     The first proportion  \r p_1 = 0.084

     The second  sample size is  n_2  =  1476000

     The  second  proportion is  \r p_2 =  0.092

Given that the confidence level is  95%  then the level of significance is mathematically represented as

      \alpha =  (100 - 95)\%

     \alpha =  0.05

From the normal distribution table  we obtain the critical value of  \frac{ \alpha }{2}  the value is  

      Z_{\frac{\alpha }{2} } =z_c=  1.96

Now using the formula from the question to construct the 95% confidence interval we have  

  (\r p_1 - \r p_2  )- z_c \sqrt{ \frac{\r p_1 \r q_1 }{n_1} + \frac{\r p_2 \r q_2 }{n_2} }

Here \r q_1 =  1 - \r p_1

  =>   \r q_1 =  1 - 0.084

 =>    \r q =  0.916

and  

   \r q_2 =  1 - \r p_2

 =>   \r q_2 =  1 - 0.092

=>   \r q_2 = 0.908

So  

 (0.084 - 0.092 )- (1.96)*  \sqrt{ \frac{0.092* 0.916 }{1068000} + \frac{0.084* 0.908 }{1476000} }

  -0.00870

 

3 0
3 years ago
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