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DedPeter [7]
3 years ago
12

(7) A 955 gram piece of tungsten metal is heated from 18°C to 100°C. The amount of heat absorbed

Chemistry
1 answer:
Ber [7]3 years ago
3 0

Answer:

The answer to your question is: Cp = 0.129 J/g°C

Explanation:

Data

mass = 955 g of tungsten

T1 = 18°C

T2 = 100°C

Q = 10180 Joules

Cp = ?

Formula

Q = mCpΔT

Clear Cp from the equation

Cp = Q / mΔT

Substitution

Cp = 10180 / (955(100-18))

Cp = 10180 / (955(82))

Cp = 10180 / 78310

Cp = 0.129 J/g°C

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maksim [4K]

Lithium has charge of +1 and bromide has charge of - 1. So they combine to form the compound lithium bromide which is expressed as LiBr.

<h3><u>Explanation:</u></h3>

Lithium is an alkali metal placed in group 1 or periodic table. It has a valency of 1 which is achieved as lithium loses an electron to achieve a charge of +1.

Bromine is a halogen which is placed in group 17 of periodic table. It has a valency of 1 which is achieved as bromine looses an election to achieve a charge of - 1.

Lithium is the cation and bromide is the anion. So lithium is written in front and bromine following the cation. And as both of their valencies are 1, so they form the compound LiBr.

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3 years ago
0.39 moles of a gas fill a 5.0 l container that connects to a balloon through a closed valve. if the valve is opened an pressure
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Answer: 5.39

Explanation: you are adding the balloon's volume and the container's volume

8 0
2 years ago
Which fossil fuel is the most abundant in the United States?
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Answer:

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Explanation:

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6 0
2 years ago
Read 2 more answers
What is the total volume of gaseous products formed when 116 liters of butane (C4H10) react completely according to the followin
Contact [7]

<u>Answer:</u> The total volume of the gaseous products is 1044.29 L

<u>Explanation:</u>

We are given:

Volume of butane = 116 L

At STP:

22.4 L of volume is occupied by 1 mole of a gas

So, 116 L of volume will be occupied by = \frac{1}{22.4}\times 116=5.18mol of butane

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+13O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

  • <u>For carbon dioxide:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 5.18 moles of butane will produce = \frac{8}{2}\times 5.18=20.72mol of carbon dioxide

Volume of carbon dioxide at STP = (20.72 × 22.4) = 464.13 L

  • <u>For water vapor:</u>

By Stoichiometry of the reaction:

2 moles of butane produces 10 moles of water vapor

So, 5.18 moles of butane will produce = \frac{10}{2}\times 5.18=25.9mol of water vapor

Volume of water vapor at STP = (25.9 × 22.4) = 580.16 L

Total volume of the gaseous products = [464.13 + 580.16] = 1044.29 L

Hence, the total volume of the gaseous products is 1044.29 L

3 0
2 years ago
In order to predict the outcome of the reaction, write the molecular, full ionic, and net ionic equations for a mixture of aqueo
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Answer:

See explanation

Explanation:

Full molecular equation;

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Full ionic equation

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Net ionic equation;

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When Silver nitrate is mixed with a solution of aqueous ammonia, a white and cloudy solution was observed.

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