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DedPeter [7]
3 years ago
12

(7) A 955 gram piece of tungsten metal is heated from 18°C to 100°C. The amount of heat absorbed

Chemistry
1 answer:
Ber [7]3 years ago
3 0

Answer:

The answer to your question is: Cp = 0.129 J/g°C

Explanation:

Data

mass = 955 g of tungsten

T1 = 18°C

T2 = 100°C

Q = 10180 Joules

Cp = ?

Formula

Q = mCpΔT

Clear Cp from the equation

Cp = Q / mΔT

Substitution

Cp = 10180 / (955(100-18))

Cp = 10180 / (955(82))

Cp = 10180 / 78310

Cp = 0.129 J/g°C

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If a gas sample has a pressure of 30.7 kPa at 0.00*C, by how much does the temperature have to decrease to lower the pressure to
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Answer:

                      252.68 K  or   -20.46 °C

Explanation:

                    According to Gay-Lussac's Law, "Pressure and Temperature at given volume are directly proportional to each other".

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                                              P₁ / T₁  =  P₂ / T₂   ---- (1)

Data Given:

                  P₁  =  30.7 kPa

                  T₁  =  0.00 °C  =  273.15 K

                  P₂  =  28.4 kPa

                  T₂  =  <u>???</u>

Solving equation for T₂,

                  T₂  =  P₂ T₁ / P₁

Putting values,

                  T₂  =  28.4 kPa × 273.15 K / 30.7 kPa

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Answer:

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Explanation:

Given data;

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from ideal gas law  we have

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