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irinina [24]
3 years ago
13

Consider a sample that is a mixture composed of biphenyl, benzoic acid, and benzyl alcohol. The sample is spotted on a TLC plate

and developed in a hexanes-ethyl acetate solvent mixture. Predict the relative Rf values for the three compounds in the sample (biphenyl, benzoic acid, and benzyl alcohol).
Chemistry
1 answer:
Citrus2011 [14]3 years ago
4 0

Answer:Consider a sample that is a mixture composed of biphenyl, benzoic acid, and benzyl alcohol. The sample is spotted on a TLC ... Predict the relative Rf values for the three components in the sample. Hint: See Table 19.3. ... The sample is spotted on a TLC plate and developed in solvent mixture. We are going to predict the ...

Explanation:MORE POWER

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If 495 milliliters of carbon dioxide at 25°C and 101.3 kilopascals reacts with excess water, what is the theoretical yield of ca
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CO_2+H_2O\rightarrow H_2CO_3

From balanced equation, there is 1:1 mol ratio between carbon dioxide and carbonic acid. So, moles of carbonic acid will be equal to the moles of carbon dioxide used.

Moles of carbon dioxide can be calculated using ideal gas law equation as it's volume, temperature and pressure are given.

we need to convert mL to L, degree C to kelvin and kilopascals to atm.

495mL(\frac{1L}{1000mL})  = 0.495 L

25 + 273 = 298 K

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= 1 atm

Ideal gas law equation is:

PV = nRT

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n=\frac{PV}{RT}

R is the universal gas constant and it's value is \frac{0.0821atm.L}{mol.K} .

Let's pug in the values in the equation and solve it for n.

n=\frac{1*0.495}{0.0821*298}

n = 0.02 mol

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Molar mass of carbonic acid = 2(1.008)+12.01+3(16.00)

= 2.016+12.01+48.00

= 62.03 gram per mol (rounded to two decimal places)

Let's multiply the moles by molar mass:

0.02mol(\frac{62.03g}{mol})

= 1.24 g

So, the theoretical yield of carbonic acid is 1.24 g.


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