Answer:
14.9802 grams of estrogen must be added to 216.7 grams of benzene.
Explanation:
The relative lowering of vapor pressure of solution containing non volatile solute is equal to mole fraction of solute.

Where:
= Vapor pressure of pure solvent
= Vapor pressure of the solution
= Number of moles of solvent
= Number of moles of solute





Mass of 0.05499 moles of estrogen :
= 0.05499 mol × 272.4 g/mol = 14.9802 g
14.9802 grams of estrogen must be added to 216.7 grams of benzene.
3.6 moles
required when each quantity of reactant completely reacts.
The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.
The balanced chemical equation is :
(l) →
(g) +
(g)
Given is = 2.6 mol 
As we see, 3 moles of
reacts with 4 moles of
.
Therefore,
n(
) = n(
) × 
n(
) = 
n(
) = 3.6 moles.
Therefores, 3.6 moles
required when each quantity of reactant completely reacts.
Learn more about moles here;
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Answer:
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Explanation:
The balanced chemical reaction to obtain water from SnO₂ is:
The mole ratio is:

Find the number of moles equivalent to 1.20× 10²¹ molecules of water, using Avogadro's number:

From the mole ratio, the number of moles of SnO₂ are half the number of moles of water. That is:
- 0.0019927 moles / 2 = 0.00099635 moles of SnO₂
Use the molar mass of SnO₂ to convert the number of moles to grams:
- molar mass of SnO₂ = 150.71g/mol
- mass of SnO₂ = 0.00099635mol × 150.71 g/mol = 0.150 grams.
The answer must be reported with 3 significant figures.
Answer:Group 1 elements have 1 valence electron, meaning they have 1 extra electron that can easily be donated to an atom in search of 1 more electron. When they give away that extra electron to form an ionic compound, they become more stable.
For example, Group 7A (Group 17) elements have 7 valence electrons, meaning they need 1 extra electron to be stable. Group 1 and 7A elements make splendid ionic compounds.
Explanation:
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