Answer:
The specific heat of gold is 0.129 J/g°C
Explanation:
Step 1: Data given
Mass of gold = 15.3 grams
Heat absorbed = 87.2 J
Initial temperature = 35.0 °C
Final temperature = 79.2 °C
Step 2:
Q = m*c*ΔT
⇒ Q =the heat absorbed = 87.2 J
⇒ m = the mass of gold = 15.3 grams
⇒ c = the specific heat of gold = TO BE DETERMINED
⇒ ΔT = The change in temperature = T2 - T1 = 79.2 - 35.0 = 44.2 °C
87.2 J = 15.3g * c * 44.2°C
c = 87.2 / (15.3 * 44.2)
c = 0.129 J/g°C
The specific heat of gold is 0.129 J/g°C
Answer:
marine biology
coastal ecology
astronomy
meteorology
Explanation:
As a college student, to study oceanography one will have to take classes in the field of marine biology, coastal ecology, astronomy and meteorology.
An oceanographer is someone or a professional that studies the ocean in order have more scientific knowledge about them.
Oceanography is a merger of geology, biology, chemistry, physics as it pertains to the ocean.
- There is no need to study human anatomy to study oceanography.
- Marine biology and coastal ecology deals with study of life forms in their marine environment.
- Astronomy and meteorology helps to gain insight about the formation of the ocean and how weather relates to the ocean.
Sun, use fusion to combine hydrogen atoms into helium atoms,
Ice starts to melt and turns into water as it melts
