1) 2K(s) + 2H₂O(l)→ 2KOH(aq) + H₂<span>(g)
This is a single replacement reaction where K reacts with H</span>₂O , displaces the H⁺ ion in water and combines with OH⁻ to form a base.
<span>
2) 2B</span>i(NO₃)₃(aq) + 3H₂S(g)→ Bi₂S₃(s) + 6HNO₃<span>(aq)
</span>This is a double displacement reaction where the ions are exchanged and form new compounds. Since ions are exchanged between 2 compounds its called double displacement.
3) 2HNO₃<span>(aq) + Ba(OH)</span>₂<span> → Ba(NO</span>₃<span>)</span>₂<span>(aq) + 2H</span>₂O<span>(l)
This is an acid base reaction where nitric acid and barium hydroxide react to form the respective salt and water</span>
Answer:
9.64
Explanation:
pH + pOH = 14
Since pOH = 4.36, pH would be:
pH = 14 - pOH
pH = 14 - 4.36
pH = 9.64
1.2 Cups to 0.2839 Liters (I think if I did my math right)
All the choices in the question are sources of error i.e.
- People observe things slightly differently and can make mistakes
- Measuring devices have limits, might be broken, or might be calibrated incorrectly
- Outside factors can affect the experiment (temperature, humidity, light, wind, etc.
- Experiments are usually not 100% accurate. This means that an experiment is most of the time, with error. Errors usually occur in measurement or observation and can cause them to be different from the true values of what is being measured.
TYPES OF ERROR:
Error can either be systematic or random.
- Random errors are errors causes by unpredictable circumstances in the experiment
- Systematic errors are caused by faulty or inaccurate instruments used.
According to this question, the following can be sources of errors in an experiment:
- People observe things slightly differently and can make mistakes
- Measuring devices have limits, might be broken, or might be calibrated incorrectly
- Outside factors can affect the experiment (temperature, humidity, light, wind, etc.
Learn more: brainly.com/question/14149934
Answer:
See below
Explanation:
Molarity = moles/Volume in Liters = (grams/formula wt)/Vol in Liters
=> Grams of solute = Molarity x Vol in Liters x formula wt
= (0.250M)(0.750L)(212.3g/mol)
= 39.8 grams