Consider Frank's math test scores for the semester. Find the interquartile range of the scores.
1 answer:
Okay so you put the numbers in order:
70, 74, 81, 82, 83, 91, 94.
Then you find the median which will be Q2:
82.
Once you have the total median, you find the midpoint of the first and last part:
70, 74, 81. Midpoint/Q1=74
83, 91, 94. Midpoint/Q3=91
Now that you have that, you subtract Q3 and Q1.
91-74=17
17 is your IQR.
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let the 2 integers be x and x + 2.
so we have the equation:-
3(x + 2) = x - 10
3x + 6 = x - 10
2x = -16
x = -8
the integers are -8 and -6 answer
Answer:
gradient:
3x+2y=5
3(1)+2dy/dx=0
3+2dy/dx=0
2dy/dx=-3
dy/dx=-3/2.
y-intersect:
3x+2y=5
2y=5-3x
y=5-3x/2
-0.83 for it’s the lowest number
z = 7√2 cos(7/8π) + 7√2i sin(7/8π) = 7√2e^(i7/8π)
Answer:
0.00274725….
Hope this helps!
