All categories

3 years ago

Consider Frank's math test scores for the semester. Find the interquartile range of the scores.

1 answer:

4 0

Okay so you put the numbers in order:
70, 74, 81, 82, 83, 91, 94.

Then you find the median which will be Q2:
82.

Once you have the total median, you find the midpoint of the first and last part:
70, 74, 81. Midpoint/Q1=74
83, 91, 94. Midpoint/Q3=91

Now that you have that, you subtract Q3 and Q1.
91-74=17

17 is your IQR.

You might be interested in

The slope of the line that passes through the points (-10,y) and (5, 2) is 2/5. What is the value of y?

Murrr4er [49]

Answer:

C, -4

Step-by-step explanation:

slope=change in y/change in x

$\frac{2 - y}{5 - ( - 10)} = \frac{2}{5}$

$\frac{2 - y}{5 + 10} = \frac{2}{5}$

multiply both sides by 2/5

$2 - y = \frac{2}{5} (5 + 10)$

simplify the right side. 2/5 × 5 = 2 and 2/5 × 10 = 4

$2 - y = 2 + 4$

$2 - y = 6$

bring y to the other side by adding y on both sides

$2 = 6 + y$

subtract 6 on both sides

$2 - 6 = y$

so y is -4

7 0

2 years ago

Dan made $5000 in taxable income last year.

storchak [24]

well, we know is 10% for the first 7500, but Dan only made 5000 of taxable income, so he's in that range of 0 - 7500, so he only gets to pay 10% of 5000.

$\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{10\% of 5000}}{\left( \cfrac{10}{100} \right)5000}\implies 500$

8 0

3 years ago

A single microvillus is a rod-like structure that is 1.0 μm in height. It has a hemispherical top approximately 0.1 μm in diamet

gregori [183]

Answer:

so, the figure here is a cylinder with a semi sphere on the top, we know the height of whole structure, and the radius of the semi sphere, which is the same as the radius of the cylinder (you can see it because the radius of the semisphere is constant, and you can thin on it as half a sphere over a cylinder).

First, the cylinder will be the structure without the semi sphere, so his height will be te total height minus the radius of the semi sphere, which is 0.9μm.

so now we know the height and the radius of the cylinder, the surface or the sides of it is 2*3.14*r*h = 2*3.14*0.9μm*0.1μm = 0.5662 $μm^{2}$ .

3 0

3 years ago

Certain gases in the atmosphere trap heat on Earth.

erik [133]

<span>C.
glacial melting<<<<<<<<<<<<<<<</span>

4 0

3 years ago

Help pleae look at the picture!

notsponge [240]

Line a and b are perpendicular

3 0

3 years ago