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3 years ago

Element X is a radioactive isotope such that every 66 years, its mass

Mathematics

1 answer:

LenKa [72]3 years ago

3 0

Answer:

194.5315427 grams

Step-by-step explanation:

The half-life of element x would be 66 years. So, after 20 years you would have:

.5^(20/66) x 240=0.810548 x 240

=194.5315427 grams of the element left ......

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Give a correct interpretation of a 99% confidence level of 0.102 < p < 0.236.

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We are 99% confident that the interval from 0.102 to 0.236 actually does contain the true value of the population proportion p.

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Answer:A number decreased by 40

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Solve the triangle. B = 36°, a = 38, c = 18

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Using cosine law.

b= sqrt(38^2 + 18^2 - 2(38)(18) Cos 36)
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The price of a sandwich is $1.50 more than the price of a smoothie, which is d dollars. What does the expression d+1.5 represent

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The expression d+1.5 represents the price of the sandwich, d in the scenario represents the smoothie price.

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This equation represents an exponential function that passes through the point (2, 80).

miss Akunina [59]

we know that

If the point belongs to the graph, then the point must satisfy the equation

we will proceed to verify each case

case A.) $f(x)=4(x^{5})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=4(2^{5})$

$f(2)=128$

$128\neq 80$

therefore

the equation $f(x)=4(x^{5})$ not passes through the point $(2,80)$

case B.) $f(x)=5(x^{4})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=5(2^{4})$

$f(2)=80$

$80=80$

therefore

the equation $f(x)=5(x^{4})$ passes through the point $(2,80)$

case C.) $f(x)=4(5^{x})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=4(5^{2})$

$f(2)=100$

$100\neq 80$

therefore

the equation $f(x)=4(5^{x})$ not passes through the point $(2,80)$

case D.) $f(x)=5(4^{x})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=5(4^{2})$

$f(2)=80$

$80=80$

therefore

the equation $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

the answer is

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

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