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Burka [1]
3 years ago
5

X + 3y =- 12 y+ 3 =- {(x – 3)

Mathematics
1 answer:
fenix001 [56]3 years ago
8 0

Answer:

x = 6, y = -6

Step-by-step explanation:

solve for x and y

x + 3y =  -12

y + 3 = -x + 3

add

(x + 3y)  +  -x + 3  =  -12 + y + 3

3y + 3 = y - 9

2y + 3 = -9

2y = -12

y = - 6

x + 3(-6) = -12

x - 18 = -12

x = 6

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5. Elijah eats of a grapefruit every morning for breakfast. Which fraction shows how many grapefruits he will eat in 7 days? SOM
dezoksy [38]

Answer:

7/2

Step-by-step explanation:

he will have eaten 3.5 grapefruits in 7 days

7/2= 3.5

3 0
2 years ago
Can anybody help me with this please
Marysya12 [62]

Jan is not correct. The opposite of any number will not always be a positive. This is because the opposite of a positive number is negative and the opposite of a negative number is positive.

Basically, opposite numbers are numbers that are the same distance to 0 on a number line. If we were to have a positive 1, the opposite of that number would be a -1, because that's equally distant from 0 on a number line.

3 0
2 years ago
Read 2 more answers
What is the possibility that a red or green marble will be selected from a bag containing 9 red marbles, 6 blue marbles , 7 gree
marusya05 [52]

Answer:

16/33

Step-by-step explanation:

We have a bag of :

9 red marbles

6 blue marbles

7 green marbles

11 yellow marbles

Total number of marbles = 33 marbles.

The possibility that a red or green marble will be selected from a bag

P( Red or Green) = P(Red) + P(Green)

In the question we are not told if it is with replacement or without. We do both

With replacement

P( R or G) = P(Red) + P(Green)

P(Red)= 9/33

P(Green) = 7/33

= 9/33 + 7/33

= 16/33

Therefore, the possibility that a red or green marble will be selected from a bag is 16/33

8 0
2 years ago
The first term of an arithmetic sequence is 7 and the sixth term is 22. Find(a)the common difference;(2)(b)the twelfth term;(2)(
SVEN [57.7K]

d = 3 , a₁₂ = 40 and Sx_{100} = 7775

In an arithmetic sequence the nth term and sum to n terms are

<h3>• an = a₁ + (n-1)d</h3><h3>• S_n = \frac{n}{2}[2a + (n-1)d]</h3><h3>where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ = \frac{50}{2}[(2×7) +(99×3)</h3><h3>       = 25(14 + 297) = 25(311)= 7775</h3>
7 0
2 years ago
Solve:<br><br> 5n = 25<br> A. n = 8<br> B. n = 5<br> C. n = 2<br> D. n = 1
Lilit [14]

Answer:

n=5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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