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3 years ago

What power output (in horsepower) of the engine of a 1.20 x 10^3 kg car if it can go from 25.0 km/hr to 100. km/hr in 12.0 s?

Physics

1 answer:

brilliants [131]3 years ago

4 0

Answer:

48.5 hp

Explanation:

$m$ = mass of the car = 1200 kg

$v_{o}$ = initial speed of the car = 25 km/hr = 6.94 m/s

$v}$ = final speed of the car = 100 km/hr = 27.78 m/s

$t$ = time interval = 12 s

Power output of the engine is given as

$P = (0.5)\left ( \frac{m}{t} \right ) (v^{2} - v_{o}^{2})$

$P = (0.5)\left ( \frac{1200}{12} \right ) (27.78^{2} - 6.94^{2})$

$P = 36178.24$ W

we know that , 1 hp = 746 W

$P = \frac{36178.24}{746}$ hp

$P = 48.5$ hp

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A block of aluminum at a temperature of T1 = 32 degrees C has a mass of m1 = 12 kg. It is brought into contact with another bloc

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Answer: $T=21.33 ^{\circ}$

Explanation:

Given

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3 years ago

Which theory states that if you are forced to smile at an event, you will enjoy it? A. The Schachter-Singer theory B. The Lazaru

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Answer:

C. The facial feedback theory

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The facial feedback theory as postulated by William James and connects back to the famous Charles Darwin talks about how facial expressions stimulate our emotional state of being. Based on this theory, the emotional experiences we have are determined by the looks on our faces.

According to the question, smiling at an event makes you enjoy it is an example of what the The facial feedback theory is explaining. Furthermore, smiling, which is a facial expression causes or stimulates an emotional state of enjoyment in that event.

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A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a

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The frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

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<h3>What's the expression of range of a projectile motion?</h3>

Range = U²× sin(2θ)/g
U= initial velocity, θ= angle of projectile and g= acceleration due to gravity
U=√{Range×g/sin(2θ)}
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<h3>What's the expression of time of flight in projectile motion?</h3>

Time of flight= (2×U×sinθ)/g
So, T= (2×22.5×sin36.5°)/9.8

= 2.73 s

Thus, we can conclude that the frog's launch speed and the time spends in the air are 22.5m/s and 2.73s respectively.

Learn more about the range and time period of projectile motion here:

brainly.com/question/24136952

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2 years ago

A +1.0 nC charge is at x = 0 cm, a -1.0 nC charge is at x = 1.0 cm and a 4.0 nC at x= 2 cm. What is the electric potential energ

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Answer:

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U = - 2.7 x 10^-6 J

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3 years ago