Brainly help this kid cause why not -_-!

Physics

2 answers:

ludmilkaskok [199]2 years ago

7 0

Answer:

The answer is 3; Zero

Explanation:

It is to remembered that at critical temperature all three phases of liquid are at equilibrium and the surface tension is zero at this temperature.

yaroslaw [1]2 years ago

3 0

Answer:

option 3. zero is the correct answer

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For study, the Earth can be divided into three parts:

erica [24]

The three parts of the Earth are Atmosphere, Hydrosphere and Lithosphere.

Atmosphere is the blanket of air that surrounds the earth. It is densest close to the surface and thins out as one moves higher. Atmosphere of Earth contains mainly Nitrogen, followed by Oxygen and small amounts of water vapor, Carbondioxide and other gases.

Lithosphere is the outer most part of the earth's surface. The Earth's crust and the mantle form Lithosphere.

Hydrosphere is the part of the Earth that has water. The Oceans, seas, rivers, lakes and other water bodies constitute the Hydrosphere.

Stratosphere, Mesosphere and Ionosphere are different layers of atmosphere.

Hence, for the study of the Earth, one needs to consider earth to be made of three parts- atmosphere, Lithosphere and Hydrosphere.

5 0

3 years ago

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What does gravity, electricity, and magnesium have in common?

Ghella [55]

Answer:

magnesium (Mg), chemical element, one of the alkaline-earth metals of Group 2 (IIa) of the periodic table, and the lightest structural metal. Its compounds are widely used in construction and medicine, and magnesium is one of the elements essential to all cellular life.

Explanation:

hope it helps

4 0

2 years ago

The polar coordinates of the collar A are given as functions of time in seconds by r = 2+ 0.7 t2 ft and ????= 3.5t rad. What are

r-ruslan [8.4K]

Answer with explanation:

Part a)

$v_{radial}=\frac{dr}{dt}=\frac{d(2+0.7t^{2})}{dt}\\\\v_{radial}=1.4t\\\\\therefore v_{radial}|_{t=4}=1.4\times 4=5.6ft/s\\\\v_{angular}=r|_{t=4}\times \frac{d\theta }{dt}=13.2\frac{3.5t}{dt}=46.2fts^{-1}\\\\\therefore v=\sqrt{v_{radial}^{2}+v_{angular}^{2}}\\\\v=46.53ft/s$

Part b)

$a_{radial}=\frac{d^{2}r}{dt^{2}}=\frac{d^{2}(2+0.7t^{2})}{dt^{2}}\\\\a_{radial}=1.4ft/s^{2}\\\\a_{angular}=r\times \frac{d^{2}\theta }{dt^{2}}\\\\a_{angular}=r\times \frac{d^{2}(3.5t) }{dt^{2}}\\\\\therefore a_{angular}=0\\\\\therefore Accleration=1.4ft/s^{2}$