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3 years ago

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Graph with points plotted at (negative 4, negative 3), (negative 1, negative 2), (negative 2, 0), (2, 2). Find the range of the

relation. {–4, –2, –1, 0, –2} {–4, 4} {–4, –2, –1, 2} {–3, –2, 0, 2}

1 answer:

Firdavs [7]3 years ago

6 0

I know the first part but not the second part. Look at the image below.

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Someone help me with this

qwelly [4]

Answer:

D

Step-by-step explanation:

there are 9 digits.

and round it off to the nearest hundred million which is 3.

There are 8 digits before the 3... so 10 gets to the power of 8.___ 10⁸

3,0×10⁸ m.s^-1

3 0

2 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!! The figure below shows the movement of a pedestrian from point B to point E. Using the

jeyben [28]

Answer:

Step-by-step explanation:

A) What is the speed of the pedestrian BC, CD, and DE?

Speed from B to C = distance/time = (40 - 20) / 4 = 20/4

= 5 km/h

Speed from C to D = distance/time = 0 / 2

= 0 km/h

Speed from D to E = distance/time = (20 - 0) / (10 - 6) = 20/4

= 5 km/h

B) After what time since the stop did he arrive at point E?

Since the stop at D, he arrived at E after (10 - 6) = 4 h

C) Write the formulas for function d(t) for sections BC, CD, and DE

For BC, d = 40 when t = 0 and d = 20 when t = 4

So d(t) = 40 - 5t

For CD, d = 20 when t = 4 and t = 6

So d(t) = 20

For DE, d = 20 when t = 6 and d = 0 when t = 10

So d(t) = 5 * (10 - t) or d(t) = 50 - 5t

4 0

3 years ago

Read 2 more answers

Can I have some help on these two math questions?

BigorU [14]

8. 1,728 i did 12×18÷2=108×32=345÷2= 1,728

8 0

3 years ago

A circle is drawn on the coordinate plane. It has a center at (2, 1) and passes through the point (2, 5). What is the approximat

ArbitrLikvidat [17]

First we need to find the radius. Using Pythagorean theorem we can find the radius which is the distance between the center and any point along the circle:

r=((5-1)^2+(2-2)^2)^(1/2)

r=(4^2-0^2)^(1/2)

r=4 units.

Circumference=2pr so our circumference is 8p units^2

Approximately 25.13 u^2

8 0

3 years ago

Two groups went bowling. Here are the scores from each group.

vladimir2022 [97]

Answer:

Group A has greater variability

Step-by-step explanation:

Group A: 80, 100, 190, 110, 70, 90, 130

The variability of group A data :

Taking the range :

Maximum = 190 ; Minimum = 70

Range = Maximum - Minimum ; 190 - 70 = 120

Group B : 50, 110, 100, 120, 107, 140, 150

The variability of group B data :

Taking the range :

Maximum = 150 ; Minimum = 50

Range = Maximum - Minimum ; 150 - 50 = 100

Hence, Group A has greater variability

6 0

2 years ago