Before the asteroid is threw, the total momentum is zero,
since neither Superman nor the asteroid are moving.
Conservation of momentum commands the total momentum after the astronaut is threw
must be zero too. This means that Superman's backward momentum afterward throwing
the asteroid is equivalent to the asteroid forwards momentum, in size.
Momentum is mass times velocity. We know the mass of the asteroid is 1000M and
its velocity is 850 m/s, so its momentum is
(1000M)(850 m/s) = 850,000M m/s.
So to get the answer: dividing by
Superman's mass, M, gives his recoil velocity o 850,000 m/s.
I believe a vector needs to be set. but no 100% sure!
I hope this helps!
Answer:
See the answers below
Explanation:
We can solve both problems using vector sum.
a)
Let's assume the forces that help the diver dive as positive downward, and the forces that oppose upward, as negative
![F_{resultant}=100+30-85+900\\F_{resultant}=845[N]](https://tex.z-dn.net/?f=F_%7Bresultant%7D%3D100%2B30-85%2B900%5C%5CF_%7Bresultant%7D%3D845%5BN%5D)
The drag force is horizontal d this way in the horizontal direction we will only have the drag force that produces the water stream.
![F_{drag}=50[N]](https://tex.z-dn.net/?f=F_%7Bdrag%7D%3D50%5BN%5D)
b)
Let's assume the forces that propel the rocket upwards as positive and forces like the weight of the rocket and other elements as negative forces.
![F_{resultant}=960+7080-7700\\F_{resultant}=340 [kN]](https://tex.z-dn.net/?f=F_%7Bresultant%7D%3D960%2B7080-7700%5C%5CF_%7Bresultant%7D%3D340%20%5BkN%5D)