The seafloor is only expanding in one area, which is the Atlantic Ocean. It's just Earth's seafloor recylcing itself.
Answer:
The work done by this engine is 800 cal
Explanation:
Given:
100 g of water
120°C final temperature
22°C initial temperature
30°C is the temperature of condensed steam
Cw = specific heat of water = 1 cal/g °C
Cg = specific heat of steam = 0.48 cal/g °C
Lw = latent heat of vaporization = 540 cal/g
Question: How much work can be done using this engine, W = ?
First, you need to calculate the heat that it is necessary to change water to steam:

Here, mw is the mass of water

Now, you need to calculate the heat released by the steam:

The work done by this engine is the difference between both heats:

Answer:
Explanation:
Effort x effort distance = load x resistance distance
effort distance = 8 m ,
load = 2000N
resistance distance = 1/2 m = 0.5 m
Putting the values in the equation above
effort x 8m = 2000N x .5
effort = 2000 x 0.5 / 8
= 125 N
force required = 125 N .
Answer:

Explanation:
Mass of the kid 23.7 kg.


We need to find the acceleration of the kid,
We know that, Parallel force acted on the kid at an angle is
F = m × g × sinθ (F = ma)
m × a = m × g × sinθ
Now, substitute the given values in the above formula to find acceleration of the kid,

23.7 × a = 232.26 × 0.733
23.7 × a = 170.24


