1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mice21 [21]
4 years ago
13

What is the base angles of a 9 sided polygon

Mathematics
1 answer:
Ivanshal [37]4 years ago
6 0

Answer:

140 degrees

Step-by-step explanation:

You might be interested in
If 3.x - 7 = 5, then 2x – 1=?
Katyanochek1 [597]

Answer: -2

Step-by-step explanation:

7 0
3 years ago
The lines are perpendicular. Find the slope-intercept form of the equation of line y₂
Alex17521 [72]
When you want to find the slope of the perpendicular line, all you have to do is flip the known slope upside down and make it negative. You know that y_{1} 's slope is 3 and you know y_{2} is perpendicular. So, just flip 3 upside down into \frac{1}{3} and then make it negative, -<span>\frac{1}{3}. If you look at the coordinate grid, you can see that y_{2} crosses the y-axis at 4. When you put those into slope-intercept form you get y_{2} = -</span>\frac{1}{3}x + 4.
4 0
3 years ago
If the integral of the product of x squared and e raised to the negative 4 times x power, dx equals the product of negative 1 ov
Nataly_w [17]

Answer:

A + B + E = 32

Step-by-step explanation:

Given

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

Required

Find A +B + E

We have:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

Using integration by parts

\int {u} \, dv = uv - \int vdu

Where

u = x^2 and dv = e^{-4x}dx

Solve for du (differentiate u)

du = 2x\ dx

Solve for v (integrate dv)

v = -\frac{1}{4}e^{-4x}

So, we have:

\int {u} \, dv = uv - \int vdu

\int\limits {x^2\cdot e^{-4x}} \, dx  = x^2 *-\frac{1}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x} 2xdx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} - \int -\frac{1}{2}e^{-4x} xdx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx

-----------------------------------------------------------------------

Solving

\int xe^{-4x} dx

Integration by parts

u = x ---- du = dx

dv = e^{-4x}dx ---------- v = -\frac{1}{4}e^{-4x}

So:

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} - \int -\frac{1}{4}e^{-4x}\ dx

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x} + \int e^{-4x}\ dx

\int xe^{-4x} dx = -\frac{x}{4}e^{-4x}  -\frac{1}{4}e^{-4x}

So, we have:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} \int xe^{-4x} dx

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} +\frac{1}{2} [ -\frac{x}{4}e^{-4x}  -\frac{1}{4}e^{-4x}]

Open bracket

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{x^2}{4}e^{-4x} -\frac{x}{8}e^{-4x}  -\frac{1}{8}e^{-4x}

Factor out e^{-4x}

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{x^2}{4} -\frac{x}{8} -\frac{1}{8}]e^{-4x}

Rewrite as:

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{1}{4}x^2 -\frac{1}{8}x -\frac{1}{8}]e^{-4x}

Recall that:

\int\limits {x^2\cdot e^{-4x}} \, dx  = -\frac{1}{64}e^{-4x}[Ax^2 + Bx + E]C

\int\limits {x^2\cdot e^{-4x}} \, dx  = [-\frac{1}{64}Ax^2 -\frac{1}{64} Bx -\frac{1}{64} E]Ce^{-4x}

By comparison:

-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2

-\frac{1}{8}x = -\frac{1}{64}Bx

-\frac{1}{8} = -\frac{1}{64}E

Solve A, B and C

-\frac{1}{4}x^2 = -\frac{1}{64}Ax^2

Divide by -x^2

\frac{1}{4} = \frac{1}{64}A

Multiply by 64

64 * \frac{1}{4} = A

A =16

-\frac{1}{8}x = -\frac{1}{64}Bx

Divide by -x

\frac{1}{8} = \frac{1}{64}B

Multiply by 64

64 * \frac{1}{8} = \frac{1}{64}B*64

B = 8

-\frac{1}{8} = -\frac{1}{64}E

Multiply by -64

-64 * -\frac{1}{8} = -\frac{1}{64}E * -64

E = 8

So:

A + B + E = 16 +8+8

A + B + E = 32

4 0
3 years ago
Solve: 5.6p = 17.36<br> p=
Levart [38]

Answer: Solving for P

P= 3.1

8 0
4 years ago
Read 2 more answers
If the measure of arc AD is 65 degrees and the measure of arc BC is 45 degrees, what is the measure of angle BEC?
krek1111 [17]

Answer:

\angle BEC=55 \textdegree)

Step-by-step explanation:

From the question we are told that:

Arc AD =65 \textdegree

Arc BC =45 \textdegree

Given The angle of intersecting chords theorem

Generally the equation for angle BEC is mathematically given by

 \angle BEC=\frac{1}{2} (\angle of arc AD+\angle of arc BC)

 \angle BEC=\frac{1}{2} (65 \textdegree+45 \textdegree)

 \angle BEC=55 \textdegree)

7 0
3 years ago
Other questions:
  • The image below shows where coal deposits are found in the United States. Explain how these coal deposits are energy sinks and c
    14·1 answer
  • Find the smallest 4-digit number perfect square.
    11·1 answer
  • A pen costs twice as much as a pencil. The total cost of 1 1 pen and 1 1 pencil is $2.10 $2.10 . If p p represents the cost of 1
    6·1 answer
  • Patti’s dance class starts at quarter past 4. At what time does her dance class start?
    15·1 answer
  • The temperature went from -16°F to 7°F. What was the change in temperature?
    8·1 answer
  • What is 0.25 kilometers expressed in centimeters?
    13·2 answers
  • PLEASE HELPPpPpppppP!!!!!!!!!!!!Determine the average rate of change of the function on the given interval.
    15·1 answer
  • Match each expression to its equivalent expression. (6+8)*x 4x+4+2 1 4(2x+3) 6x+8X 1 6(x+y+z) 8x+4+3 1 4(x+2) 6х+бу+6z​
    9·1 answer
  • What is the approximate value of q in the equation below? q log subscript 2 baseline 6 = 2 q 2
    9·1 answer
  • Find the volume of the right cone below in terms of π.<br> hight 9<br> diamiter 6
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!