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Oliga [24]
2 years ago
7

What is the answer to this problem? Please help me

Mathematics
1 answer:
aksik [14]2 years ago
5 0

Answer:

C

Step-by-step explanation:

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P and Q are two points on the line x - y + 1 = 0 and are at distance 5 from the origin. Find the area of the triangle OPQ. ​
Alecsey [184]

Answer:

P and Q are two points on the line x-y+1=0 and are at a distant of 5 units from the origin. Find the area of triangle POQ.

Step-by-step explanation:

P and Q are the intersection points of

x-y+1 = 0 and the circle x^2 + y^2 = 25

sub y = x+1 into the circle

x^2 + (x+1)^2 = 25

x^2 + x^2 + 2x + 1 - 25 = 0

x^2 + x - 12 = 0

(x+4)(x-3) = 0

x = 3 or x = -4

y = 4 or y = -3

so P(3,4) and Q(-4,3) are our two points

Height of triangle.

h = |0 - 0 + 1|/√2 = 1/√2

PQ = √( (-7)^2 + 1^2) = √50 = 5√2

area POQ = (1/2)(1/√2)(5√2) = 5/2 square units

hope this helped

7 0
2 years ago
(1,2) and (7,9) I need to find the slope of that
ehidna [41]

Answer:

7/6 is your slope,,,,,

8 0
3 years ago
Read 2 more answers
(64/8/ 4 + 7 – 2) • 5 =
maria [59]

Answer:

35

Step-by-step explanation:

Let me know if I got it right

3 0
2 years ago
3<2x-4<8 help plz im, in a tesyt
Anastaziya [24]

Answer:

7/2<x<6

Step-by-step explanation:

i think is this wait for someone ele to answer to be sure

4 0
3 years ago
Consider the population consisting of all computers of a certain brand and model, and focus on whether a computer needs service
eimsori [14]

Answer and explanation:

A. What is the probability that more than half of the sample of 100 computers would need warranty service?

What is the probability that more than half of the sample of 100 computers would not need warranty service?

What is the probability that out of sample of 100 more than 20% would require warranty service?

B. If our sample of 100 computers of that brand and model reveals that 30 computers need warranty service, does this give a valid conclusion that all such computers in the population would require about 30% warranty service or less?

7 0
3 years ago
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