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luda_lava [24]
3 years ago
8

Which shows the correct way to use the rule ""multiply by the reciprocal"" for the expression below? 7 divided by StartFraction

5 Over 8 EndFraction StartFraction 1 Over 7 EndFraction times StartFraction 5 Over 8 EndFraction = StartFraction 5 Over 56 EndFraction StartFraction 7 Over 1 EndFraction times StartFraction 5 Over 8 EndFraction = StartFraction 35 Over 8 EndFraction StartFraction 1 Over 7 EndFraction times StartFraction 8 Over 5 EndFraction = StartFraction 8 Over 35 EndFraction StartFraction 7 Over 1 EndFraction times StartFraction 8 Over 5 EndFraction = StartFraction 56 Over 5 EndFraction
Mathematics
2 answers:
guajiro [1.7K]3 years ago
5 0

Given:

The expression is \dfrac{7}{\frac{5}{8}}.

To find:

The shows the correct way to use the rule ""multiply by the reciprocal"" for the given expression.

Solution:

According to the rule "multiply by the reciprocal", if a,b,c,d are four number, then

\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}

We have,

\dfrac{7}{\frac{5}{8}}

It can be written as

\dfrac{7}{\frac{5}{8}}=\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}

Using the rule "multiply by the reciprocal", we get

\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{7}{1}\times \dfrac{8}{5}

\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{7\times 8}{1\times 5}

\dfrac{\dfrac{7}{1}}{\dfrac{5}{8}}=\dfrac{56}{5}

Therefore, the correct option is D.

liq [111]3 years ago
5 0

Answer:

The correct answer is C.

Step-by-step explanation:

Hope this helps!

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Find (a) arc length and (b) Area of a sector.
barxatty [35]

Answer:

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b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

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\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

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\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}

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