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Triss [41]
3 years ago
12

Colby wants to set square tiles on the top of a wooden box. The top of the box is a rectangle 7 1/2 inches long and 5 1/2 inches

wide.
a. How many 1/2 inch tiles would Colby need to cover the top of the wooden box?
b. How many 1/4 inches tiles would Colby need to cover the top the wooden the box?
Mathematics
1 answer:
Sever21 [200]3 years ago
8 0
You will need 82 1/4 1/2 tiles and 165 1/4 tiles 
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VMariaS [17]
The slope is the slope :D
4 0
2 years ago
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<img src="https://tex.z-dn.net/?f=1%20%2B%20%20log_%7B2%7D%28x%20-%202%29%20%20%3D%20%20%20log_%7B2%7Dx" id="TexFormula1" title=
fenix001 [56]

Move all the logarithms on the left hand side, and all the constants on the other:

\log_2(x-2) - \log_2(x) = -1

Use the rule of logarithms

\log_a(b) - \log_a(c) = \log_a\left(\dfrac{b}{c}\right)

To rewrite the equation as

\log_2\left(\dfrac{x-2}{x}\right) = -1

Evaluate 2 to the power of each side:

\dfrac{x-2}{x} = 2^{-1} = \dfrac{1}{2}

Multiply both sides by 2x:

2(x-2) = x \iff 2x-4 = x \iff x = 4

6 0
3 years ago
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Find the arc length of the semicircle.
makkiz [27]
I think it’s 15.71
5 0
2 years ago
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What is the slope of this line?
MrMuchimi

We can use the coordinates (-4, 5) and (0, 6) to find the slope.

Slope Formula: \frac{y2-y1}{x2-x1}

Solve: \frac{6 - 5}{0 - (-4)} = \frac{1}{4}

The slope of the line is \Large\boxed{\mathsf{1/4}}

Written in slope-intercept form: y = 1/4x + 6

Hope This Helped! Good Luck!

3 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST!!
VMariaS [17]

Answer:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

Step-by-step explanation:

The given trapezoid has vertices at A(−1,4), B(0,2), C(1,2) and D(2,4).

The transformation rule for 90° counterclockwise rotation is

(x,y)\to(-y,x)

This implies that:

A(-1,4)\to A'(-4,-1)

B(0,2)\to B'(-2,0)

C(1,2)\to C'(-2,1)

D(2,4)\to D'(-4,2)

This is followed by a translation 3 units to the right.

This also has the rule: (x,y)\to (x+3,y)

A'(-4,-1)\to A''(-1,-1)

B'(-2,0)\to B''(1,0)

C'(-2,1)\to C''(1,1)

D'(-4,2)\to D''(-1,2)

Therefore:

A(-1,4)\to A''(-1,-1)

B(0,2)\to B''(1,0)

C(1,2)\to C''(1,1)

D(-2,4)\to D''(-1,2)

3 0
3 years ago
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