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Ira Lisetskai [31]
3 years ago
8

Bank of America’s _____________ provides information such as its interest expense, or the interest the bank paid depositors, and

its interest income, or the interest it earned by investing deposits over a period of time. This document also states the bank’s other revenues and expenses for the time period. 1. leverage ratio 2. activity ratio 3. income statement 4. balance sheet
Business
1 answer:
OleMash [197]3 years ago
5 0

Answer:

3. income statement

Explanation:

Bank of America’s income statement provides information such as its interest expense, or the interest the bank paid depositors, and its interest income, or the interest it earned by investing deposits over a period of time. This document also states the bank’s other revenues and expenses for the time period.

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The cash records of Oriole Company show the following. For July: 1. The June 30 bank reconciliation indicated that deposits in t
inysia [295]

Explanation:

a.  Deposit in Transit at July 31 = Deposit in Transit, June 30 + Deposit as per Cash Book – Deposits as per Bank Book

= $690 + $17,970 - $15,770

= $2,890

b.  Outstanding Checks at July 31 = Outstanding Checks at June 30 + Checks issued as per Cash Book – Checks cleared as per Bank Book

= $930 + $19,160 - $16,800

= $3,290

c.  Deposits in Transit at August 31 = Deposits as per Bank Statement – Deposits as pr Books + Deposits in Transit, September 30

= $26,750 - $26,340 + $2,810

= $3,220

d.  Outstanding Checks at August 31 = Checks cleared by Bank – Cash Disbursements as per Books + Outstanding Checks, September 30

= $24,370 - $23,030 + $2,440

= $3,780

8 0
3 years ago
What difficulties may come when the proffession
antiseptic1488 [7]

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1. Lack of Vision

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5. Fear

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7 0
3 years ago
You are considering a project with an initial cost of $7,500. What is the payback period for this project if the cash inflows ar
Sliva [168]

Answer:

A. 3.21 years

Explanation:

In the payback, we analyze in how many years the invested amount is recovered. The computation is shown below:

In year 0 = $7,500

In year 1 = $1,100

In year 2 = $1,640

In year 3 = $3,800

In year 4 = $4,500

If we sum the first 3 year cash inflows than it would be $6,540

Now we deduct the $6,540 from the $7,500 , so the amount would be $960 as if we added the fourth year cash inflow so the total amount exceed to the initial investment. So, we deduct it

And, the next year cash inflow is $4,500

So, the payback period equal to

= 3 years + $960 ÷ $4,500

= 3.21 years

In 3.21 yeas, the invested amount is recovered.  

4 0
3 years ago
This is my mom channel please subscribe<br><br>I need 300 subscribe ​
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ok, but can u mark me brainliest? that would really help.... :)

3 0
3 years ago
A metallurgist has one alloy containing 26%26% copper and another containing 69%69% copper. How many pounds of each alloy must h
Brilliant_brown [7]

Answer:

Ans. He must use 2,987.76 pounds of alloy X (Cu=69%) and 2,365.24 pounds of alloy Y (26%=Cu)

Explanation:

Hi, let´s call alloy X the alloy that contains 69% of Cu and alloy Y the one containing 26% of Cu. Since he needs to produce 5,353 pounds of alloy, the first equation that we need to use is the following.

X+Y=5,353

Now, we need this 5,353 pounds of the new alloy to be 50% Cu, therefore, we have to use a portion of alloy X and alloy Y. This is as follows.

0.69X+0.26Y=0.5(X+Y)

And we have already established that X+Y is equal to 5,353, therefore this equation should look like this.

0.69X+0.26Y=5,353*0.5

0.69X+0.26Y=2,676.5

And we solve for X this equation, this as follows.

0.69X=2,676.5-0.26Y

X=\frac{2,676.5-0.26Y}{0.69}

X=3,878.98-0.3768Y

Now, we use this result and substitute this for X in the first equation like this.

3,878.98-0.3768Y+Y=5,353

and then, we solve for Y

0.6232Y=5,353-3,878.98

Y=\frac{1,474.02}{0.6232} =2,365.24

So, he needs to use 2,365.24 pounds of alloy that contains 26% of Cu, this means that the rest (2,987.76 pounds) must come from the alloy that contains 69% of Cu.

We can check this result by finding the overall Cu obtained by this amounts of alloy, that is

Coppper FromX=2,987.76*0.69=2,061.55

Coppper FromY=2,365.24*0.26=614.96

That adds up to 2,676.51 pounds of pure Cu, and since the total weight of the new alloy is 5,353, this amount of copper makes up for:

PercentCu=\frac{2,676.51}{5,353} =0.5

50% of the total weight.

Best of luck.

7 0
3 years ago
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