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Charra [1.4K]
3 years ago
9

Nathan is going to a water park today. He knows that the cost of admission is at least $12 per person. If c stands for the cost

of admission, which of the following inequalities represents the cost of admission for the water park?
Mathematics
1 answer:
mash [69]3 years ago
8 0
C \geq $12

If the cost c is at least $12 then it could be equal to 12, or could also be a cost greater than $12. So, c is greater than or equal to 12, expressed as <span>c \geq $12</span>
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In a coin collection, the number of dimes is 6 more than twice the number of nickels. If the collection has 36 dimes, how many n
kodGreya [7K]

Answer: The answer is 78

Step-by-step explanation:

Since it said the number of dimes is 6 more than twice the number of nickels There are 36 dimes, this statement in an equation is d=(2n + 6), so then it would be [2(36) + 6] which is 72 + 6 = 78

5 0
3 years ago
Please help with question
Step2247 [10]
To solve this problem you must apply the proccedure below:

 1. Let's call:

 x: hot dogs.
 y: hamburguers.

 2. Then, you must make a system of equations, as below:

 5x+4y=12.25  (i)
 4x+5y=12.50  (ii)

 3. Now, you can solve the system of equation as below:

 5x+4y=12.25
 x=(12.25-4y)/5

 4x+5y=12.50
 4((12.25-4y)/5)+5y=12.50
 y=1.5

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 4x+5(1.5)=12.50
 x=1.25

 4. Therefore, the answer is:

 The cost of one hot dog is $1.25 and the cost of one hamburguer is $1.50
 
8 0
2 years ago
Suppose that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water
Setler79 [48]

Answer:

Step-by-step explanation:

Given that a large mixing tank initially holds 400 gallons of water in which 70 pounds of salt have been dissolved. Pure water is pumped into the tank at a rate of 4 gal/min, and when the solution is well stirred, it is then pumped out at the same rate.

Let Q(t) be the quantity of salt at time t.

Q(0) = 70 pounds

Inflow of water = outflow = 4 gal/min

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Use when t =0 Q = 70

A =70

So A(t) = Q(t) = 70 e^{-\frac{t}{400}} and

A(0) = Q(0) = 70 lbs.

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2 years ago
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Put x=5 in above function. J(x)= 39x. J(5) = 39x5 = 195.
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